Answer:By 8(4)P.5, the slope of the line equally inclined to axes is tan(±45
o
)=±1. Hence by P+λQ=0,
5λ+3
2λ+4
=±1
⇒λ=
3
1
,−1. Putting for λ, the two lines are
x−y=0,x+y−2=0.
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Answer:
50
Step-by-step explanation:
53.042 -3.350 = 49.692---> 50
Answer:
y = -6
x = 1
Step-by-step explanation:
-x + 2y = -13
-x - 2y = 11
Sum the equations:
-x -x = -2x
+2y - 2y = 0
-13 + 11 = -2
then
-2x = -2
x = -2/-2
x = 1
from the first eq.
-x + 2y = -13
-1 + 2y = -13
2y = -13 + 1
2y = -12
y = -12/2
y = -6
check:
from the second eq.
-x -2y = 11
-1 -(2*-6) = 11
-1 -(-12) = 11
-1 + 12 = 11
Answer:
Step-by-step explanation:
N(17+x)=34x−r
17n+xn=34x-r
xn= 34x - r - 17n
xn-34x= -r - 17n
x(n-34)= -r - 17n
x= (-r - 17n)/(n-34)
