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Evgesh-ka [11]
3 years ago
12

Write √ 45 + √ 20 in the form k √ 5

Mathematics
2 answers:
prohojiy [21]3 years ago
3 0

Answer:

5sqrt(5)

Step-by-step explanation:

sqrt(45)+sqrt(20)

sqrt(9*5)+sqrt(4*5)

sqrt(9)sqrt(5)+sqrt(4)sqrt(5)

3sqrt(5)+2sqrt(5)

(3+2)sqrt(5)

5sqrt(5)

BabaBlast [244]3 years ago
3 0

√45 = √9×5 = 3√5

√20 = √4×5 = 2√5

____________________

√45 + √20 ===》 3√5 + 2√5 = 5√5

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Hey! 2 to the power of 5 is 2 x 2 x 2 x 2 x 2 which equals 32.

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Simplify algebraic equation x^2-4/x^2+2x
hram777 [196]

Answer:

Simplification of algebric expression is \frac{x^{2} - 2x^{3}-4 }{x^{2} }

Step-by-step explanation:

Simplify any algebric expression means to write an equivalent expression in which all similar terms combined and remove all symbols such as brackets.

The given algebraic equation is x^{2} -\frac{4}{x^{2} } +2x

now for simplifying it

First of all take L.C.M of x^{2}

= \frac{x^{2} (x^{2}) -4 + 2x(x^{2} )}{x^{2} }

We get \frac{x^{2} -4+2x^{3}}{x^{2} }

Further we can write it as  \frac{x^{2} - 2x^{3}-4 }{x^{2} }

Simplification of algebric expression is \frac{x^{2} - 2x^{3}-4 }{x^{2} }

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7 0
3 years ago
63° 55°<br> X =<br> degrees.
lorasvet [3.4K]

Answer:

Step-by-step explanation:

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a sociologist develops a test to measure attitudes towards public transportation and 27 randomly selected subjects are given the
horsena [70]

Answer:

The 95% confidence interval for the mean score is:

\mu ∈ (67.73,\ \ 84.67)

Step-by-step explanation:

We want to estimate the population mean, that is, the average score of all the subjects.

An estimator for the population mean μ is {\displaystyle {\overline {x}}}

Since the sample size is 27 then we use the  statistic  t_{\frac{\alpha}{2}}  with 27-1 = 26 degrees of freedom

The confidence interval for the mean is:

({\displaystyle {\overline {x}}} + t_{\frac{\alpha}{2}}\frac{S}{\sqrt{n}},\ \ {\displaystyle {\overline {x}}} - t_{\frac{\alpha}{2}}\frac{S}{\sqrt{n}})

Where

{\displaystyle {\overline {x}}}=76.2 is the average score of the sample

S=21.4 is the standard deviation of the sample

n= 27 is the sample size

t_{\frac{\alpha}{2}} = 2.056 for a confidence level of 95% and 26 degrees of freedom

Then confidence interval is

(76.2 + 2.056\frac{21.4}{\sqrt{27}},\ \ {76.2 - 2.056\frac{21.4}{\sqrt{27}})

(76.2 + 8.467,\ \ 76.2 - 8.467)

\mu ∈ (67.73,\ \ 84.67)

7 0
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