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cricket20 [7]
2 years ago
8

May I please receive help?

Mathematics
1 answer:
Artyom0805 [142]2 years ago
6 0

4, -1/4 -1,

we can do this simply by

(y2-y1)/(x2-x1)

and simplifying

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Can anyone help me out? That would be greatly appreciated!
SOVA2 [1]

B. SAS

Pretty much the way I look at it, there is one angle, and 2 sides beside it. Easiest way for me to explain.

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Hansika paid $9.25 for 2.8 pounds of pretzels. About how much did she pay for a pound of pretzels? ( Round your answer to the ne
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Given m || n, which pair of angles are not vertical angles?
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If x and ​(19x+30​) are the measures of complementary​ angles, what is the measure of each​ angle?
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3° and 87°

Step-by-step explanation:

<em>here's</em><em> your</em><em> </em><em>solution</em>

<em> </em><em>=</em><em>></em><em> </em> we know that measure of complementary angle is 90°

=>. one angle is. = x

=> other angle is .= (19x + 30)

=> so, x + 19x + 30° = 90°

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7 0
3 years ago
What is the product?
Tanzania [10]

Answer:

=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}

Step-by-step explanation:

\begin{pmatrix}-3&4\\2&-5\end{pmatrix}\begin{pmatrix}3&-2\\ 1&0\end{pmatrix}

Multiply the row of the first matrix to the column of the second matrix

\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=\left(-3\right)\cdot \:3+4\cdot \:1

\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=\left(-3\right)\left(-2\right)+4\cdot \:0

\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=2\cdot \:3+\left(-5\right)\cdot \:1\

\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=2\left(-2\right)+\left(-5\right)\cdot \:0\

=\begin{pmatrix}\left(-3\right)\cdot \:3+4\cdot \:1&\left(-3\right)\left(-2\right)+4\cdot \:0\\ 2\cdot \:3+\left(-5\right)\cdot \:1&2\left(-2\right)+\left(-5\right)\cdot \:0\end{pmatrix}

simplifying them we get

=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}

8 0
3 years ago
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