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Nataly [62]
3 years ago
10

I like rocks and rocks

Mathematics
1 answer:
Bess [88]3 years ago
5 0

FRRRRRR?!?!?!?!?!?!?!?!?!

Step-by-step explanation:

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A landscape design company is building a large gazebo for a backyard. It is in the shape of the
IceJOKER [234]

The area of the heptagon will be 533.61 square feet. Then the cost of the gazebo's flooring will be $ 5336.1.

<h3>What is a polygon?</h3>

The polygon is a 2D geometry that has a finite number of sides. And all the sides of the polygon are straight lines connected to each other side by side.

A landscape design company is building a large gazebo for a backyard. It is in the shape of the regular polygon shown below, where the measurements are in feet.

A heptagon is given with an apothem of 12.6 ft and a side length of 12.1 ft.

Then the area of the heptagon is given as

Area of heptagon = 7 x area of a triangle

Area of heptagon = 7 x 0.5 x 12.1 x 12.6

Area of heptagon = 533.61 square ft

If the costs $10 per square foot for the special wood the homeowner wants.

Then we have

Total cost = 10 x 533.61

Total cost = $ 5336.1

More about the polygon link is given below.

brainly.com/question/17756657

#SPJ1

4 0
3 years ago
Please help fast! I'm being timed. <br> What is the value of x?
Naddika [18.5K]

That's Intersecting Secants, and we get


EC × ED = EB × EA


(x+4)(x+4+1) = (x+1)(x+1+11)


(x+4)(x+5) = (x+1)(x+12)


x^2 + 9x + 20 = x^2 + 13x + 12


8 = 4 x


x = 2


Check: 3(14)=42 6(7)=42 good


Answer: 2




6 0
3 years ago
LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6
USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

The coordinates are given as:

\mathbf{(x,y) = (-60,0)\ (60,0)}

The center of the hyperbola  is  

\mathbf{(h,k) = (0,0)}

The distance from the center to the focal points is given as:

\mathbf{c = 60}

Square both sides

\mathbf{c^2 = 3600}

The distance from the receiver to the transmitters  is given as:

\mathbf{2a = 100}

Divide both sides by 2

\mathbf{a = 50}

Square both sides

\mathbf{a^2 = 2500}

We have:

\mathbf{b^2 = c^2 - a^2}

This gives

\mathbf{b^2 = 3600 - 2500}

\mathbf{b^2 = 1100}  

The equation of an hyperbola is:

\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}

So, we have:

\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}

\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Hence, the equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Read more about hyperbolas at:

brainly.com/question/15697124

7 0
3 years ago
Read 2 more answers
Pl help me to do it​
mixas84 [53]

Answer:

Step-by-step explanation:

Assuming you want to find the value of n.

\sqrt{\frac{p}{q} } =(\frac{q}{p}) ^{1-2n} \\

Remember when bases are same exponents can be made equal

Here the bases are different

because notice on one side there is p/q and on the other q/p

what can we do to make them same?

You can invert the any side you want either make leftside as q/p or make right one as p/q

I will make left side as q/p

All you do is flip the denominator and numerator to do so. But that can only be done if you put a (-1) in the exponent

so underroot p/q means (p/q)^1/2 when i make it q/p

a negative one needs to be put in the exponent. That -1 when multiplied by 1/2 makes it -1/2

Now the bases are same such like.

(\frac{q}{p} )^{-1/2} = (\frac{q}{p}) ^{1-2n}

See now the bases are same, the powers can be made equal

so

-1/2=1-2n

here n is the variable we need to find

rearrange the equation

n=3/4

3 0
3 years ago
How many positive integers less than 500 have an odd number of factors?
Tema [17]

Answer:

22

Step-by-step explanation:

Remark

Very nice little problem.

At first you think you need to go through the entire number system from 1 to 500. For example, you could do 12 as 1 2 3 4 6 12 So 12 does not add to the number of integers that have an odd number of factors.

But along the way if you check all the factors of the integers from 1 to 12, you notice something very odd. (No pun intended).

1 only has 1 factor which is odd (not even).

4 has 3 factors 1 2 4 which is odd.

9 has 3 factors 1 3 9 which is odd.

It turns out that there are 22 numbers from 1 to 500 that have an odd number of factors. They are the perfect squares between 1 and 500

Note

The factors of an integer include 1 and the integer itself

As a conclusion, try 36

1 2 3 4 6 9 12 18 36  There's 9 factors which is odd. So only the perfect squares have an odd number of factors.

5 0
3 years ago
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