okay... THE ANS IS 5/35 IS THE RIGHT ONE
Answer:
-1
Step-by-step explanation:
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
Solution:
Let f be the bags of flour and b be the pounds of butter.
Cost of 20 bags of flour 16 pound of butter = 110
⇒ 20f + 16b = 110 -------------------- (1)
Cost of 30 bags of flour 12 pound of butter = 120
⇒ 30f + 12b = 120 -------------------- (2)
Equation (1) and (2) are the system of equations.
(2) ⇒ 30f + 12b = 120
Subtract 30f from both sides.
⇒ 12b = 120 – 30f
Divide by 12 on both sides.
-------------------- (3)
Substitute (3) in (1).




Subtract 160 from both sides.

Divide by –20, we get

f = 2.50
Substitute f = 2.5 in equation (3), we get


b = 3.75
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75





<h2>Note that this problem can be approached in many ways. For instance, we can add to the b² term instead of changing the middle term...</h2>
Answer:
4^y = x + 3
2^y = x + 2
Step-by-step explanation:
log_4(x + 3 ) = log_2 (2 + x )
log_4( x + 3 ) = y
log_2 (2 + x ) = y
4^y = x + 3
2^y = x + 2