Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
Answer:
0.347
Step-by-step explanation:
n = 3
p = 1/6
r = 1
Use binomial probability:
P = nCr pʳ qⁿ⁻ʳ
P = ₃C₁ (1/6)¹ (5/6)³⁻¹
P = 0.347
Or, using a calculator:
P = binompdf(n, p, r)
P = binompdf(3, 1/6, 1)
P = 0.347
Answer:
Hey mate here is your answer...
Step-by-step explanation:
smaller circular table to be made
with a diameter only half as big... and diameter of big table is (2*55)= 110cm.... So half diameter of big is (110/2)= 55cm
therefore, diameter of smaller table is 55cm and radius of it's (55/2)= 27.5cm
circumference of circle = 2πr
= 2*3.14*27.5
= 172.7 cm = 27.5cm
hope it helps you ❣️
Answer:
3/2
Step-by-step explanation:
Apply exponent rule: a^-1 = 1/a
(2/3)^1 = 1/2/3
Apply the fraction rule: 1/a/c = c/b
3/2