Solution:
we are given that
A jury pool consists of 50 potential jurors.
Wee have been asked to find the number of ways can a jury of 12 be selected.
As we know from the concept of combination that r person can be selected out of n in ncr ways. where

Now substitute the values we get

Hence the required number of ways is 121399651100
Answer:
there will be 537 items in the library
Step-by-step explanation:
The sum of all edges is 108 cm.
There are two bases whose edges are all 8 cm; this gives us 8(4)+8(4) = 32+32=64.
There are 4 edges between bases that are 11 cm each; 11(4) = 44
Together, this gives us 64+44=108 cm.
Answer:
61%
Step-by-step explanation:
it's really simple just take the percentage of both numbers, 42% and 19% and add them together and whatever the sum is, is gonna be your answer!
Answer:
u=4
v=2√3
Step-by-step explanation:
The 30-60-90 triangle theorem states that the shortest side of a triangle is half of the hypotenuse, so 2*2=4. So, the hypotenuse, <em>u</em>, is 4.
The longest leg is √3 times greater than the shortest leg, so 2*√3=2√3. So, the longest leg, <em>v</em>, is 2√3.