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Ray Of Light [21]

3 years ago

15

Naz decided to travel to Europe last summer. The jet flew at an average rate of 550 mph and covered 3437.5 miles. How long was t

he flight to Europe?

1 answer:

melisa1 [442]3 years ago

4 0

Answer
6 hours and 25 mins Tell me if I’m wrong

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Teresa gave two-thirds of her peanuts to Gabe. Then she gave ine-half of the remaining peanuts to Carlos. She had 1 peanuts left

alukav5142 [94]

Answer:

Brainliest

Step-by-step explanation:

1 peanut before giving half

1 +1 = 2

2 before giving 2/3

2 x 3/2 = 6/2 = <em><u>3</u></em>

4 0

4 years ago

Read 2 more answers

If 1 loaf of bread is cut into slices, and each slice is 1/2 of a loaf. How many slices are there?

kvasek [131]

Answer:

2

Step-by-step explanation:

Because if you have 1 cut it in half that’s 2 slices

8 0

3 years ago

Can someone help me?

IrinaVladis [17]

Answer:

D.

Step-by-step explanation:

I think, don't trust me.

3 0

3 years ago

Can pie be written as a natural number

Elodia [21]

For example, 5 can be written as 5/1. The natural numbers, whole numbers, and integers are all subsets of rational numbers. In other words, an irrational number is a number that can not be written as one integer over another. It is a non-repeating, non-terminating decimal.

7 0

3 years ago

A rectangle is constructed with its base on the x-axis and two of its vertices on the parabola yequals25minusxsquared. What are

Karolina [17]

Answer:

The answer is " $\bold{\frac{32}{3}}\\$ "

Step-by-step explanation:

The rectangle should also be symmetrical to it because of the symmetry to the y-axis The pole of the y-axis. Its lower two vertices are (-x,0). it means that

and (-x,0), and (x,0). Therefore the base measurement of the rectangle is 2x. The top vertices on the parabola are as follows:

The calculation of the height of the rectangle also is clearly 16-x^2, (-x,16,-x^2) and (x,16,-x^2).

The area of the rectangle:

$A(x)=(2x)(16-x^2)\\\\A(x)=32x-2x^3$

The local extremes of this function are where the first derivative is 0:

$A'(x)=32-6x^2\\\\32-6x^2=0\\\\x= \pm\sqrt{\frac{32}{6}}\\\\x= \pm\frac{4\sqrt{3}}{3}\\\\$

Simply ignore the negative root because we need a positive length calculation

It wants a maximum, this we want to see if the second derivative's profit at the end is negative.

$A''\frac{4\sqrt{3}}{3} = -12\frac{4\sqrt{3}}{3}$

8 0

3 years ago