Applying Pythagorean Theorem

What is the missing reason in step 5?

DENIUS [597]

Answer:

The Correct Answer On Edgen2020 Is

A) Linear pair postulate.

Good Luck!! :))

7 0

3 years ago

Read 2 more answers

you and 3 friends go to lunch and ordered nachosthat cost 10.30. each person also orders a soda at 1.50. write an equation to sh

kicyunya [14]

Answer:

y = 4(10.30+1.50)

Step-by-step explanation:

Since there are 4 people, you and 3 others, you would multiply everything by 4. Inside the parenthesis, would be the nachos and a drink that everyone got. Since all four people got the same thing, it would be 4x10.30 + 4x1.50, which together would be y = 4(10.30+1.50)

5 0

3 years ago

Which of the following options have the same value as 20% of 45 (choose 3 answer)

11Alexandr11 [23.1K]

Answer:

20% of 45 is 9,

Step-by-step explanation:

So the answer must be 9 for an example 50% of 18 is 9 because to find 50% of something simply divide by 2 .10% of 90 is 9 because to find 10% of something divide by 10. 25% of 36 is 9 because you divide by 4 to get 25% of anything.

3 0

3 years ago

2.Each purse contains 8 coins. Find a rule to give the total number of coins.

Masja [62]

If we have to find the total number of coins then we can use the following rule:

If Each Purse Contains 8coins ,then we can find total number of coins by multiplying 8 to the number of total purse

Thus,

︎⠀⠀ ⠀⠀ ⠀⠀ ⠀︎⠀⠀ ⠀⠀ ⠀8×Total Number of Purse.

4 0

2 years ago

What is a cubic polynomial function with zeros 3,3 and -3? show your work.

Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is $\mathbf{x^3-3x^2-9x+27=0}$

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

$(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0$

So, cubic polynomial function with zeros 3,3 and -3 is $\mathbf{x^3-3x^2-9x+27=0}$

4 0

2 years ago