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nalin [4]
3 years ago
9

Find the area of the rectangle park whose length is 2 3/5 m breadth and is 4/9 metre.

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

Area = 1\frac{7}{45}m^2

Step-by-step explanation:

<u><em>Area of rectangle = Length * Width </em></u>

'Where Length = 2\frac{3}{5} and Width = \frac{4}{9}

Area = 2\frac{3}{5} × \frac{4}{9}

Area = \frac{13}{5} × \frac{4}{9}

Area = \frac{13*4}{5*9}

Area = \frac{52}{45}

Area = 1\frac{7}{45}m^2

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Answer:

I love Skittles

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4 0
3 years ago
The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm^2/
VARVARA [1.3K]

Answer:

The base is decreasing at 2 cm/min.

Step-by-step explanation:

The area (A) of a triangle is given by:

A = \frac{1}{2}bh   (1)

Where:

b: is the base

h: is the altitude = 10 cm

If we take the derivative of equation (1) as a function of time we have:

\frac{dA}{dt} = \frac{1}{2}(\frac{db}{dt}h + \frac{dh}{dt}b)

We can find the base by solving equation (1) for b:

b = \frac{2A}{h} = \frac{2*120 cm^{2}}{10 cm} = 24 cm

Now, having that dh/dt = 1 cm/min, dA/dt = 2 cm²/min we can find db/dt:

2 cm^{2}/min = \frac{1}{2}(\frac{db}{dt}*10 cm + 1 cm/min*24 cm)

\frac{db}{dt} = \frac{2*2 cm^{2}/min - 1 cm/min*24 cm}{10 cm} = -2 cm/min    

         

Therefore, the base is decreasing at 2 cm/min.

               

I hope it helps you!  

7 0
3 years ago
I need help, 15 points!
Ira Lisetskai [31]

Answer:

3(a + 5b + 7c) and 2x(2 + 5y + 11z)

Step-by-step explanation:

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3 years ago
One number is 4 more than another, and their sum is 60. What is the smaller number?
ivanzaharov [21]
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5 0
3 years ago
Mary brought a pair of jeans and a sweater. The pair of jeans costs $30 and the sweater $35. If sales tax is 6%, how much did Ma
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Answer:

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A: 67 dollars and 10 cents

3 0
3 years ago
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