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4 years ago

Find the area of the rectangle park whose length is 2 3/5 m breadth and is 4/9 metre.

Mathematics

1 answer:

snow_lady [41]4 years ago

4 0

Answer:

Area = $1\frac{7}{45}m^2$

Step-by-step explanation:

<u><em>Area of rectangle = Length * Width </em></u>

'Where Length = $2\frac{3}{5}$ and Width = $\frac{4}{9}$

Area = $2\frac{3}{5}$ × $\frac{4}{9}$

Area = $\frac{13}{5}$ × $\frac{4}{9}$

Area = $\frac{13*4}{5*9}$

Area = $\frac{52}{45}$

Area = $1\frac{7}{45}m^2$

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Answer:

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Step-by-step explanation:

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3 years ago

The square of a number decreased by 3 times the number 28 find all possible values for the number

stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

$a^2 - 3a = 28$

$a^2 - 3a - 28 = 0$

Let us solve the above quadratic equation

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text { For } a^{2}-3 a-28=0 \text { we have } a=1, b=-3, c=-28$

$\begin{aligned}&a=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(1)(-28)}}{2 \times 1}\\\\&a=\frac{3 \pm \sqrt{9+112}}{2}\\\\&a=\frac{3 \pm \sqrt{121}}{2}=\frac{3 \pm 11}{2}\\\\&a=\frac{3+11}{2} \text { or } a=\frac{3-11}{2}\\\\&a=7 \text { or } a=-4\end{aligned}$

Thus the possible values of number are 7 and -4

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3 years ago

Please answer this question only if you know it! 25 points and brainliest!

krok68 [10]

Answer:

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Step-by-step explanation:

Step 1. Calculate θ

$\begin{array}{rcll}70^{\circ} + \theta + 60^{\circ} & = & 180^{\circ} & \text{Angles of straight line}\\130^{^{\circ}} + \theta & = & 180^{\circ}} & \\\theta & = & 50^{\circ} & \\\end{array}$

Step 2. Calculate x

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3 years ago