The only formula that can be used to describe the sequence is definitely the third one
![f(x + 1) = -3/4 f(x)](https://tex.z-dn.net/?f=f%28x%20%2B%201%29%20%3D%20-3%2F4%20f%28x%29)
. So count like that
![64* -\frac{3}{4} = -48 48* -\frac{3}{4} = 36](https://tex.z-dn.net/?f=64%2A%20-%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20-48%0A48%2A%20-%5Cfrac%7B3%7D%7B4%7D%20%3D%2036%20)
and so on. You can check others by yourself to check if I'm right or not.
I hope this helps you
(fog)(5)=f (g (5))=?
x= 5 g (5)=-4.5+3=-20+3=-17
f (g(5))=f (-17)=-2. (-17)-7
f (-17)=34-7
f (-17)=27
Answer:
R(16,-8)
Step-by-step explanation:
if (x1,y1) and (x2,y2) are coordinates of two points and (x,y) the coordinate of midpoint.
then x=(x1+x2)/2
and y=(y1+y2)/2
let coordinates of R are (x,y)
4=(-8+x)/2
8=-8+x
x=8+8=16
-3=(2+y)/2
-6=2+y
y=-6-2=-8
so R is (16,-8)
Answer:
Anticlockwise 60°
Step-by-step explanation:
Let my starting point be 0°
Turning to the right(clockwise)40° = 0° + 40° = 40°
I am now at 40° to the right of my starting point.
Turning to the left(anticlockwise) 70° = 40° - 70° = -30°
I am now 30° to the left of my starting point.
Turning to the right 90° = -30° + 90° = 60°
I am 60° to the right of my starting point.
To go back to the startoing point(0°), I should go to the left(anticlockwise) by 60°
This is a change of -60°
-Chetan K