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vovikov84 [41]
3 years ago
14

This is so confusing pleasee help

Mathematics
1 answer:
densk [106]3 years ago
6 0

Answer: C

Step-by-step explanation: None of the x values repeat

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Which angle measures create a triangle with three different side lengths?
White raven [17]
It would be the angles 13*, 66*, 101* because they add up to be 180
5 0
4 years ago
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[3]<br>(b)<br>Calculate the values of c for which 2x2 – 3x + c&gt;-2 for all values of x.​
hoa [83]

Answer:

  c > -7/8

Step-by-step explanation:

Add 2 for an inequality that compares to zero:

  2x^2 -3x +(c+2) > 0

This will be true when the discriminant is negative. For the quadratic ...

  ax^2 +bx +c

the discriminant is ...

  b^ -4ac

We want this to be negative:

  (-3)^2 -4(2)(c+2) < 0

  9 -8(c +2) < 0

  9 -8c -16 < 0

  -7 < 8c

  -7/8 < c

The given inequality will be true for all values of c greater than -7/8.

3 0
3 years ago
Laura is on the swim team. Each day she swims 800 m. How many kilometers does she swim each day? Be sure to include the correct
kap26 [50]

Answer:

0.8 km

Explanation:

<u>Given she swims</u>:

  • 800 m

<u>Conversion</u>:

  • 1 km ↔ 1000 m

<u>In kilometers</u>:

  • (800/1000) km = 0.8 km
3 0
2 years ago
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Jean throws a ball with an initial velocity of 64 feet per second from a height of 3 feet. Write an equation and answer the ques
Ganezh [65]
<h2>a. What is your equation?</h2>

This is a problem of projectile motion. A projectile is an object you throw with an initial velocity and whose trajectory is determined by the effect of gravitational acceleration. The general equation in this case is described as:

h(t)=-\frac{1}{2}gt^2+v_{0}t+h_{0}

Where:

h(t): \ height \ at \ any \ time \\ \\ g: \ acceleration \ due \ to \ gravity \ 9.8m/s^2 \ or \ 32.16ft/s^2 \\ \\ v_{0}= \ Initial \ velocity

So:

v_{0}=64ft/s \\ \\ h_{0}=3ft

Finally, the equation is:

h(t)=-\frac{1}{2}(32.16)t^2+(64)t+3 \\ \\ \boxed{h(t)=-16.08t^2+64t+3}

<h2>b. How long will it take the rocket to reach its maximum height?</h2>

The rocket will reach the maximum height at the vertex of the parabola described by the equation h(t)=-16.08t^2+64t+3. Therefore, our goal is to find t at this point. In math, a parabola is described by the quadratic function:

f(x)=ax^2+bx+c

So the x-coordinate of the vertex can be calculated as:

x=-\frac{b}{2a}

From our equation:

a=-16.08 \\ \\ b=64 \\ \\ c=3

So:

t=-\frac{64}{2(-16.08)} \\ \\ \boxed{t=1.99s}

So the rocket will take its maximum value after 1.99 seconds.

<h2>c. What is the maximum height the rocket will reach?</h2>

From the previous solution, we know that after 1.99 seconds, the rocket will reach its maximum, so it is obvious that the maximum height is given by h(1.99). Thus, we can find this as follows:

H_{max}=h(1.99)=-16.08(1.99)^2+64(1.99)+3 \\ \\ \boxed{H_{max}=66.68ft}

So the maximum height the rocket will reach is 66.68ft

<h2>d. How long is the rocket in the air?</h2>

The rocket is in the air until it hits the ground. This can be found setting h(t)=0, so:

0=-16.08t^2+64t+3 \\ \\ Applying \ quadratic \ formula: \\ \\ t_{12}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=-16.08 \\ \\ b=64 \\ \\ c=3 \\ \\ t_{12}=\frac{-64 \pm \sqrt{64^2-4(-16.08)(3)}}{2(-16.08)} \\ \\ t_{1}=4.0264 \\ \\ t_{2}=-0.046

We can't have negative value of time, so the only correct option is t_{1}=4.0264 and rounding to the nearest hundredth we have definitively:

\boxed{t=4.03s}

3 0
4 years ago
Point B is on line segment AC. Given BC=9 and AB=11, determine the length AC.
Oxana [17]

Answer:

20

Step-by-step explanation:

If point B is on line segment AC, then we know for sure AB + BC = AC.

To understand this better, draw a line segment, then put a point anywhere on the line segment. There are two line segment divided by that point. If you combine those two line segments then you have your original figure.

So 11 + 9 = 20.

4 0
4 years ago
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