I need help on this if you know all the answers that would be great but if not I understand I am just struggling
2 answers:
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Answer:
60
Step-by-step explanation:
We have been given the matrix;
For a 2-by-2 matrix, the determinant is calculated as;
( product of elements in the leading diagonal) - (product of elements in the other diagonal)
determinant = ( 5*4) - (8*-5)
= 20 - (-40) = 60
The length and width of the rectangle are 7.90 inches and 31.6 inches respectively
It is given that,
Let the length of the rectangle = l
Let the width of the rectangle = w
The perimeter of the rectangle = 250 inches
l x w = 250 ....eq 1
Then,
Length is 4 times as big as width
4l = w
We need to find, the length and width of the rectangle
Putting the value of w in eqn 1
We get,
Similarly, we can get,
w = 4l
w = 4 x 7.90
w = 31.6
Hence, the length and width of the rectangle are 7.90 inches and 31.6 inches respectively
To learn more about, perimeter, here
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