Need help with this. Please

Mathematics

1 answer:

labwork [276]2 years ago

5 0

Triangle SUT is an isosceles triangle and you can prove this by a geometric proof.
We can set SU = ST.
2x + 11 = 11x - 16

Solve for x:
9x = 27
x = 3

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NEED HELP ASAP!!! 20 POINTS, 5 STAR REVIEW AND BRAINLIEST TO WHOEVER IS FIRST!

lesya [120]

Answer:

#1 is 30 degrees

#2 is obtuse

#3 is "No rhombuses are rectangles"

#4 is D

#5 is A

Step-by-step explanation:

For #1, we have an angle vertical to 120 degrees which includes a right angle, so we make an equation:

90+x=120

x=30

So angle x is 30 degrees aka. Option A

For #2, obtuse angles have the sum of the square of the side lengths that are less than the square of the hypotenuse. In this case, 6^2+4^2<9^2 or 50<81

For #3, rhombuses have two pairs of congruent sides but no right angles while rectangles have two pairs of congruent sides but they also have right angles.

For #4, they are similar because one of the triangles is dialated by a scale factor of 1.5.

For #5, just think of turning the triangle on its other side, aka. option A

4 0

3 years ago

Read 2 more answers

The 3rd and 6th term of a geometric progression are 9/2 and 243/16 respectively find the first term, common ratio, seventh term

sashaice [31]

Answer:

Hello,

Step-by-step explanation:

$Let\ (u_n)\ the\ geometric\ progression.\\\\r\ is\ the\ common\ ratio.\\\\u_3=u_0*r^3\\u_6=u_0*r^6\\\\\dfrac{u_6}{u_3} =r^3=\dfrac{\frac{243}{16} }{\frac{9}{2} } =\dfrac{27}{8} =(\frac{3}{2} )^3\\\\\boxed{r=\dfrac{3}{2} }\\\\\\u_3=u_1*r^2 \Longrightarrow\ u_1=\dfrac{u_3}{r^2} =\dfrac{\frac{9}{2} }{(\frac{3}{2^2}) } =2\\\\\\u_7=u_6*\dfrac{3}{2} =\dfrac{729}{32}$