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zhannawk [14.2K]
3 years ago
12

1. Which of the following is not true about reflections?

Mathematics
1 answer:
forsale [732]3 years ago
5 0

Answer:c

Step-by-step explanation:

Think about it this way when you look into a round puddle you see your reflection and the puddle is neither horizontal or veritical

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What are five costs related to business?
ANTONII [103]

Answer:

Advertising and promotion.

Borrowing costs.

Employee expenses.

Equipment and supplies.

Insurance, license, and permit fees.

Research expenses.

Technological expenses.

Step-by-step explanation:

7 0
3 years ago
2x+4y=-12 and -4x-2y=-12 what is the solution
DochEvi [55]

Answer:

The answer is that x = 6 and y = -6

Step-by-step explanation:

In order to find these values, we can use elimination. To do so, we multiply the first equation by 2 and then add the equations together.

4x + 8y = -24

-4x - 2y = -12

------------------

6y = -36

y = -6

Now that we have this value, we can plug the value into one of the originals and find x.

2x + 4y = -12

2x + 4(-6) = -12

2x - 24 = -12

2x = 12

x = 6

4 0
4 years ago
Which of the following represents the approximate circumference of a circle with a diameter of 5.8 ft? A. 9.106 ft C. 18.212 ft
mario62 [17]

Answer:

C-18.212 feet

Step-by-step explanation:

7 0
3 years ago
A horse ran 800 meters in 40 seconds , 1200 meters in 60 seconds , and 480 meters in 24 seconds . Is this a proportional relatio
frosja888 [35]

Answer:

This is a proportional relationship, the constant of proportionality is 20m/s and it represents that the horse can run 20 meters every second.  

Equation:  d = 20s, where d=distance and s=number of seconds.

Step-by-step explanation:

In order to find out whether this relationship is proportional, you need to see if the rate at which the horse runs is constant (the same).  If you look at the three sets of data (24, 480), (40, 800) and (60, 1200) where the pair is (seconds, meters), you can see that for any two sets of data the change in meters divided by the change in seconds is consistently 20m/s.  For example:

\frac{1200-800}{60-40}=\frac{400}{20}=20

Since the constant is 20, we know that the horse can run 20 meters every second.  To find the horse's total distance, we need to multiply the rate by the number of seconds that it runs:

d = 20s

8 0
4 years ago
Please help me solve for x
kkurt [141]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

The shown pair of angles are Co interior angle pair, therefore the sum of those angles is 180°

\qquad \sf  \dashrightarrow \: 130 \degree + 7x + 1 \degree = 180 \degree

\qquad \sf  \dashrightarrow \: 131 \degree + 7x = 180 \degree

\qquad \sf  \dashrightarrow \:  7x= 180 \degree - 131 \degree

\qquad \sf  \dashrightarrow \:  7x= 49 \degree

\qquad \sf  \dashrightarrow \:  x=49 \degree \div 7

\qquad \sf  \dashrightarrow \:  x=7 \degree

The required value of x is 7°

3 0
3 years ago
Read 2 more answers
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