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4vir4ik [10]
3 years ago
9

Write the gcf of: 200x^2y^5 and 1000x^3y^2

Mathematics
1 answer:
gulaghasi [49]3 years ago
7 0

Answer:

Step-by-step explanation:

200 divides into 1000 so that is part of the HCF.

x^2 and x^3 are present so the HCF contains x^2

y^2 and y^5 are present so the HCF contains y^2

HCF = 200*x^2 * y^2

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DIA [1.3K]

It is not binomial random variable , since the number of red cards is unknown in the deck of cards in the starting of experiment.

As given in the question,

Number of cards are unknown.

Number of red cards are unknown in the starting of experiment.

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For binomial random variable number of red cards should be known.

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8 0
2 years ago
Which property of addition is shown in the equation below?
andrezito [222]

Answer:

i think its identity

Step-by-step explanation:

because ur adding zero

i might be wrong, i dont know

7 0
3 years ago
Read 2 more answers
1 of 4
Serhud [2]
7 Did occurred twice. So 7 is the mode.
4 0
3 years ago
Your school is organizing a carnival. You are building a ramp for a game. The surface of the ramp will be 7 feet long with a tot
meriva
The correct answer is C
4 0
3 years ago
the sum of the digits of a two number is 14 .if 36 is substracted from the number,the places of the digits are reversed.find the
Taya2010 [7]
The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x

Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y

10y+ x-36=10x+y
Substitute y with 14-x
So we would get

10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5

Y=14-x
=14-5
=9


So the two digit number is
10y+x
=90+5
=95
5 0
3 years ago
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