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gulaghasi [49]
3 years ago
14

Please help asap!!!!!!!

Mathematics
1 answer:
Liula [17]3 years ago
4 0
X2522+=x yes yes definitely it
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Help with these questions
balandron [24]

9514 1404 393

Answer:

  16) No

  17)  (c)

Step-by-step explanation:

For a lot of multiple-choice matrix problems, a simple test is all that is needed to determine the correct answer.

16) The determinant of A is (-2)(-2) -(2)(-3) = 10. So, we expect to see values in the inverse matrix that are 0.2 and 0.3. Alas, they're not there. The matrices are not inverses.

  A^-1 = [[-.2, .3][-.2, -.2]]

__

17) The matrices are both 3×3, so their product is possible (eliminates choice D). The upper left term is different among the answer choices, so we can determine the correct one by computing that term only.

  BA=C

  c11 = (5)(1) +(7)(5) +(3)(-1) = 5 +35 -3 = 37

This matches the third choice (C).

If you use a calculator to compute the full matrix product, it matches choice C in all details.

6 0
3 years ago
If the value of the blur radius is _____, no shadow will appear
vladimir1956 [14]

The value of the Blur radius is zero

Then no shadow will appear.

4 0
3 years ago
Prime fractorization of 140/700
BaLLatris [955]
<span>Prime factorization of 140/700 = </span>Answer: 140/700 =1/5 = 0.2
5 0
3 years ago
Sita and Radha purchased a car for rupees 320000 due to some economic problem they sold it for 280000.find the loss incured and
musickatia [10]

Answer:

40000 and 12.5% respectively

Step-by-step explanation:

soln:

given,

cost price(c.p)=320000

selling price(s.p)=280000

loss(l),loss percentage(l%)=?

we know,

l=c.p-s.p

or,l=320000-280000

•°•l=40000

now,

l%=l/c.p*100%

or,l%=40000/320000*100%

•°•l%=12.5%

6 0
3 years ago
Martiza remembers her pin because it is between 1000 and 1500 and it is a product of two consecutive prime numbers what is her p
Anna71 [15]

Answer:

Her pin must be 1147

Step-by-step explanation:

A little trick I have up my sleeve when I have these kind of questions is that I find the square root of each number, then find what is prime.

\sqrt{1000}  = 31.6

\sqrt{1500} = 38.7

Since the only prime numbers in the range of 31 and 38 is 31 and 37.

We can then multiply 31 by 37 to get 1147.

6 0
3 years ago
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