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Mashutka [201]
3 years ago
15

Which expression has a solution of 6, if r=4

Mathematics
2 answers:
podryga [215]3 years ago
7 0
R+2 hope you have a good day and pass
Pani-rosa [81]3 years ago
5 0

r+2

Explanation:

because if we add 2 to r which is equal to 4 we can get 6

You might be interested in
Explain and show plz
STALIN [3.7K]

C,D and F are correct.

C is what you would think of when reading it, you walked 12 and walked 1/4(12) more.

12 + 12(1/4) =

12 + 3 =

15

D is equal to C when simplified,

12(1+1/4) =

12 + 3 =

15

F is the same as the D, it just simplified the numbers in the parenthesis

12(1+1/4) =

12(4/4 + 1/4) =

12(5/4) =

15

8 0
3 years ago
Read 2 more answers
Q # 1 simplify the expression
Agata [3.3K]
<u>Answer</u>

95,040

<u>Explanation</u>
The interpretation of this expression is; the number of permutation of 5 objects out of 12.

12P5 = 12!/(12-5)!

         =12!/7!
         =(12×11×10×9×8×7×6×5×4×3×2×1)/(7×6×5×4×3×2×1)

         =12×11×10×9×8
         =95,040

5 0
3 years ago
Is the answer B correct?
VashaNatasha [74]
If you do the elimination process, here it is.

- A : Too small

+ B : I think so

- C : I little too big

- D : Way too big
7 0
3 years ago
Read 2 more answers
Find the indicated real nth root(s) of a. n=3, a=729
marissa [1.9K]

Answer:

9

Step-by-step explanation:

n=3, a=729

For any odd integer, n ; a will have only one real nth root which will be a positive integer.

Similarly, for any integer, n, that is > 1 ; related by the expression ;

p^n = a ; the nth root of a = p

Therefore,

If n = 3 ; a = 729

p^3 = 729

To obtain the value of p ; take the cube of both sides

(p^3)*1/3 = 729^1/3

p = 9

Hence, the real nth root of 729 is +9 when n = 3

6 0
2 years ago
A ball is thrown directly up in the air from a height of 5 feet with an initial velocity of 60 ft/s. Ignoring air resistance, ho
Mice21 [21]

Answer:

3.8 seconds

Step-by-step explanation:

Given equation

h= -16t^2 + 60t + 5

When the ball hits the ground then height is 0

So we replace h with 0 and solve for t

0= -16t^2 + 60t + 5

a= -16 , b= 60 and c= 5

Apply quadratic formula to solve for t

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

=\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}

=\frac{-60+-28\sqrt{5}}{-32}

=\frac{4(-15+-7\sqrt{5})}{-32}

=\frac{(-15+-7\sqrt{5})}{-8}

Now make two fractions and solve for x

t= -\frac{7\sqrt{5}-15}{8}=-0.0815

t= \frac{7\sqrt{5}+15}{8}=3.83

So answer is 3.8 seconds


4 0
3 years ago
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