|r+3| = (r+3) when r ≥ -3 so for r ≥ -3
r + 3 ≥ 7
r ≥ 4
|r+3| = -(r+3) when r < -3 so for r < -3
-(r + 3) ≥ 7
r + 3 ≤ -7
r ≤ -10
The answer to this question is r ≤ -10, r ≥ 4
The answer should be option C.
Answer: C
Step-by-step explanation: It’s C , I had the same question.
Total number of ways to make a pair:
The first player can be any one of 7 . For each of those . . .
The opponent can be any one of the remaining 6 .
Total ways to make a pair = 7 x 6 = 42 ways .
BUT ... every pair can be made in two ways ... A vs B or B vs A .
So 42 'ways' make only (42/2) = 21 different pairs.
If every pair plays 2 matches, then (21 x 2) = <em><u>42 total matches</u></em> will be played.
Now, is that an elegant solution or what !
Answer:
Affects
Step-by-step explanation:
Consider point (2,-1).
1. Reflect it in the line y=x, then the image point will have coordinates (-1,2). Now reflect it in the x-axis, then the image point will have coordinates (-1,-2).
2. Reflect the point (2,-1) in the x-axis. Its image is point (2,1). Reflect this point in the line y=x, then its image will be point (1,2).
Since images in 1st case and 2nd case differ, the order affects the final image.
