Answer:
#1. Identity #2. 0 #3. No solution
Step-by-step explanation:
#1.
5y + 2 = (1/2)(10y+4)
5y + 2 = 5y + 2
This would be identity as the equation of the left and right are the same. This is not to be confused with no solution(explained below).
#2.
0.5b + 4 = 2(b+2)
0.5b + 4 = 2b + 4
0.5 b - 2b = 0
b = 0
#3.
-3x + 5 = -3x + 10
This equation has no solution because when you try to bring the -3x to one side, the x variable itself gets eliminated. So, how is it different from identity? Well in the first equation, it is true that when we try to bring the 5y one side it eliminates the y variable, however, that is also true for the constants(since if we try to bring the 2 to one side, it will be 2-2 which will equal 0, thus eliminating each other), but in this case, even if we remove the x, the constants will not equal 0, thus it will have no solution.
For this case we can make the following rule of three:
9 1/2 m --------------> 28 1/2 rupees
26 1/3 m -------------> x
From here, we clear the value of x.
We have then:
Rewriting we have:
Answer:
samruth should pay 79 rupees to the shopkeeper
(24)(20)2= 960 the answer to the question
The best way to answer this item is to use the Substitution method. Substitute the value of y from the first equation to the y of the second equation such that the second equation becomes,
-4x + 3(x - 4) = -3
Simplifying the equation,
-x = 9
Dividing both sides by -1 gives an answer of,
<em>x = -9</em>
Then, substitute the value of x in the first equation.
y = -9 - 4
<em> y = -13</em>
The answer to this item is letter B.
Step-by-step explanation:
Use formula to find the slope/gradient
(-5, -1) = (x1, y1)
(5, 11) = (x2, y2)
So,
