43 ÷ (-7) i need a answer quick
2 answers:
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Answer:
8333.33
Step-by-step explanation:
Given that the rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt, where P is the initial rate. Use the improper integral
∫^[infinity]_0 Pe^-kt dt
with P = 50 to find the total amount of the waste that will enter the atmosphere for each value of k.
k=0.06
Hence the total amount of waste that can enter the atmosphere when k =0.06 is given by
Substitute limits
=8333.33