Use the three conditions to show that function f(x)=2x^2 +3x - 1 is continuous at x=0.
1 answer:
Answer:
f(x) = 2x^2 +3x - 1
f'(x) = 4x + 3
f''(x) = 4
f(0) = 2(0)^2 + 3(0) - 1 = -1 (valid)
f'(0) = 4(0) + 3 = 3 (valid)
f''(0) = 4 (valid)
=> f(x) is continous at x = 0
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