if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation
now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.
well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys
-4------------(-1)------------2
so the vertex is at x=-1, namely the axis of symmetry is x = -1.
Answer:
itd x=68 and y=5 I apolgize if its wrong
Answer:
A set of parametric equations for the line y = 4x - 5 is;
x = t
y = 4t - 5
Step-by-step explanation:
To find a set of parametric equations for the line y = 4x - 5;
We can assign either variable x or y equal to the parameter t, in this case we can easily let x = t
We then substitute x = t in the original equation;
y = 4t - 5
Therefore, a set of parametric equations for the line y = 4x - 5 is;
x = t
y = 4t - 5
<em>45 = 6n + 3n
45 = 9 n
dividing 9 on other side
45 / 9 = n
5 = n
or
n = 5 answer..</em>
