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Elena-2011 [213]
4 years ago
7

How do I solve this math question ?

Mathematics
2 answers:
exis [7]4 years ago
5 0
5x^2=75  divide both sides by 5

x^2=15 take the square root of both sides

x=√15
svlad2 [7]4 years ago
3 0
You do the square root of 75
and then with that number you divide it by 5
and that is your answer
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Select all line segment measurements below that could NOT be used to form a triangle. a triangle with the side measurements of 3
KonstantinChe [14]

Answer:

a triangle with the side measurements of 5, 5, and 5 inches

Step-by-step explanation:

a^2+b^2=c^2

3 0
3 years ago
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NISA [10]

Answer:

Step-by-step explanation:

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3 years ago
Write a quadratic equation given the roots -1/3 and 5, show your work
Travka [436]

\boxed{(x - a)(x - b) = 0}

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

x =  -  \frac{1}{3}  \\ x = 5

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

(x +  \frac{1}{3} )(x -  5) = 0

Here we can convert the expression x+1/3 to this.

x +  \frac{1}{3}  = 0 \\  3x + 1 = 0

Rewrite the equation.

(3x + 1)(x - 5) = 0

Simplify by multiplying both expressions.

3 {x}^{2}  - 15x + x - 5 = 0 \\ 3 {x}^{2}  - 14x  - 5 = 0

<u>Answer</u><u> </u><u>Check</u>

Substitute the given roots in the equation.

3 {(5)}^{2}  - 14(5)  - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0

3( -  \frac{1}{3} )^{2}  - 14( -  \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) +  \frac{14}{3}  - 5 = 0 \\  \frac{1}{3}  +  \frac{14}{3}  -  \frac{15}{3}  = 0 \\  \frac{15}{3}  -  \frac{15}{3}  = 0 \\ 0 = 0

The equation is true for both roots.

<u>Answer</u>

\large \boxed {3 {x}^{2}  - 14x - 5 = 0}

8 0
3 years ago
You read 9.75 pages in your science book and 24.5pages of a play for English class. It takes you 1.2minutes to read each page of
drek231 [11]

Answer:

the number of time spend in reading is 31.3 minutes

Step-by-step explanation:

The computation of the number of time spend in reading is as follows:

= 9.75 pages in science book × 1.2 minutes + 24.5 pages in english class × 0.8 minutes

= 11.7 minutes + 19.6 minutes

= 31.3 minutes

Hence, the number of time spend in reading is 31.3 minutes

The same is relevant and considered

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3 years ago
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Nata [24]

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Look at the attachment for the work.

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