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4 years ago

How do I solve this math question ?

Mathematics

2 answers:

exis [7]4 years ago

5 0

5x^2=75 divide both sides by 5

x^2=15 take the square root of both sides

x=√15

svlad2 [7]4 years ago

3 0

You do the square root of 75
and then with that number you divide it by 5
and that is your answer

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AB and DE are chords that intersect at point F inside circle C as shown. If the measure of arc EA= 50 degrees and the measure of

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Answer:

Part 1) $m\angle AFE=55^o$

Part 2) $m\angle EFB=125^o$

Step-by-step explanation:

Part 1) what is the measure of angle AFE

we know that

The measure of the interior angle is the semisum of the arches that comprise it and its opposite.

<u>Note:</u> In this problem the correct measure of arc EA is 40 degrees (see the picture)

$m\angle AFE=\frac{1}{2}(arc\ EA+arc\ DB)$

substitute the given values

$m\angle AFE=\frac{1}{2}(40^o+70^o)=55^o$

Part 2) what is the measure of angle EFB?

we know that

$m\angle AFE+m\angle EFB=180^o$ ---> by supplementary angles (form a linear pair)

substitute the given value

$55^o+m\angle EFB=180^o$

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4 years ago

QUESTION IS DOW BELOW 30 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP

ivann1987 [24]

The required solution is ∠RQT = 202° and ∠QTS = 51°

<h3 />

<h3>What is a cyclic quadrilateral?</h3>

A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.

Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.

Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°

Since,sum of the opposite angles of a cyclic quadrilateral = 180°

⇒∠QTS + ∠QRS = 180°

⇒ ∠QTS + ∠129° = 180°

⇒ ∠QTS = 180° - ∠129°

⇒ ∠QTS = 51°

Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.

More about cyclic quadrilateral :

brainly.com/question/14323008

#SPJ1

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2 years ago