The car's average rate is 43.7 mph. The bicycle's average rate is 12.3 mph.
To get this solution, let the bicycle's average rate be (x) and the car's average rate be (x + 31.4) mph.
Distance= Speed x Time
364 = (x + x + 31.4) 6.5
364 = (2x + 31.4) 6.5
364/6.5 = 2x + 31.4
56 = 2x + 31.4
56 - 31.4 = 2x
24.6 = 2x
24.6/2 = x
12.3 = x
x = 12.3 mph
x+31.4 = 43.7 mph
Step-by-step explanation:
0/1,1/1
Multiply it by any number
0/1×30=0/30
1/1×30=30/30
Now we have many choices
2/30,5/30,20/30,15/30.....so...on
Answer:
In AMNO, n = 92 inches, N=119° and 20=20°. Find the length of m, to the nearest 10th of an inch In AJKL, j = 9.6 inches, k = 6.4 inches and I=8.4 inches. Find the measure of K to thelaearest degree. In AQRS. q = 49 cm, 7.1 cm and S=70°. Find the area of AQRS, to the nearest 10th of a square centimeter Find all angles, 0 = 0 < 360°, that satisfy the equation below, to the nearest 10th of a degree. 25 sino-1=0 Find all angles, 0 SC <360°, that satisfy the equation below, to the nearest tenth of a degree (if necessary). 12 sin C + 6 = 5 sin ( + 6
Step-by-step explanation:
All triangles have angles that sum to 180 degrees.
So,
Angle C = 180 - 35 - 40
Angle C = 105 degrees
Answer:
-450
Step-by-step explanation:
Say the first number is x to get the idea.
The first 150 terms are 150x - 5 * 150
15x - 750
300 - 750 = -450
