<span>The
third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15))
</span>The solution would be like this
for this specific problem:</span>
<span>2^5 =
32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is
cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even
intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians.
</span>
<span>Roots
are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15
(or 7 pi /5 ).</span>
Ok so to make this easier which problem are we working on? 9, 10, or 11? cause before I do the hard work, I need to know
Answer:
a)P=0.42
b) 
Step-by-step explanation:
We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:
a) we have k=2, n=10 and p=0.01:
b) We have, 
, Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.
Answer:
17.3
Step-by-step explanation:
50 - 32.7 = 17.3
