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Elena-2011 [213]
3 years ago
7

How do I solve this math question ?

Mathematics
2 answers:
exis [7]3 years ago
5 0
5x^2=75  divide both sides by 5

x^2=15 take the square root of both sides

x=√15
svlad2 [7]3 years ago
3 0
You do the square root of 75
and then with that number you divide it by 5
and that is your answer
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A pane of glass should be 26 inches wide by 32 inches long. The tolerance is 3/16 inch. Find the tolerance interval for each dim
wlad13 [49]

Answer:

what

Step-by-step explanation:

5 0
3 years ago
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Which of the following is a third root of the given complex number? 27(cos(pi/5)+isin(pi/5))
Digiron [165]
<span>The third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15)) 

</span>The solution would be like this for this specific problem:</span>   <span>2^5 = 32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians. </span>   <span>Roots are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15 (or 7 pi /5 ).</span>
5 0
3 years ago
Algebra: solve for x. show work to justify your answer. ​
Vinil7 [7]

Ok so to make this easier which problem are we working on? 9, 10, or 11? cause before I do the hard work, I need to know

5 0
2 years ago
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Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10
AnnyKZ [126]

Answer:

a)P=0.42

b) n\geq 297

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}

a) we have k=2, n=10 and p=0.01:

P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42

b) We have, 1-(1-p)^n=P, Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.

1-0.99^n\geq 0.95\\0.99^n\leq 1-0.95\\0.99^n\leq 0.05\\n\geq 297

4 0
2 years ago
Hi, help ASAP please.
Kisachek [45]

Answer:

17.3

Step-by-step explanation:

50 - 32.7 = 17.3

7 0
2 years ago
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