All categories

3 years ago

What is the author's purpose in “Malala the Powerful”?

Mathematics

2 answers:

jolli1 [7]3 years ago

6 0

Answer

Step-by-step explanation:

i took the test

nlexa [21]3 years ago

4 0

Answer:

to explain how education systems around the world differ

Step-by-step explanation:

You might be interested in

Matrix C is a transformation of matrix B, and matrix is a transformation of matrix A as shown below.

blsea [12.9K]

Answer:

answer 2

Step-by-step explanation:

3 0

4 years ago

I need to know how to do this, plz explain-Which function grows at the fastest rate for increasing values of x?

saul85 [17]

If the first function is
.. h(x) = 2^x
it will be the one that grows the fastest. The exponential function with the largest base value will grow faster than any polynomial.

7 0

3 years ago

Read 2 more answers

Find the values of x,y,and z

iren2701 [21]

Answer:

Step-by-step explanation:

In parallelogram opposite sides are equal.

y = 12

x = 5

In parallelogram diagonals bisect each other

z = 8

4 0

3 years ago

Given f(x) = x − 7 and g(x) = x2 . What does f(g(4)) =

Stells [14]

Answer:

Step-by-step explanation:

f(x) = x − 7

g(x) = x^2

Find g(4) = 4^2 = 16

Then find f(g(4)) = f(16) = 16 -7 = 9

3 0

3 years ago

Read 2 more answers

A camera is mounted at a point 4000 feet away from a geyser. If the water is rising vertically at 900 ft/s when it is 3000 feet

Leno4ka [110]

Answer:

$\dot \theta = 0.144\,\frac{rad}{s}$ , $\dot \theta = 8.251\,\frac{deg}{s}$ (Option B)

Step-by-step explanation:

The trigonometric diagram is included herein as attachment. The expression is presented below:

$\tan \theta = \frac{y}{x}$

Where:

$x$ - Horizontal distance between the geyser and the camera.

$y$ - Vertical distance between the geyser and the camera.

The rate of change in terms of time is:

$\dot \theta \cdot \sec^{2}\theta = \frac{\dot y\cdot x-y\cdot \dot x}{x^{2}}$

$\dot \theta \cdot \left(\frac{1}{\cos^{2}\theta} \right) = \frac{\dot y \cdot x - y\cdot \dot x}{x^{2}}$

$\dot \theta = \left(\frac{\dot y \cdot x - y \cdot \dot x}{x^{2}} \right)\cdot \cos^{2}\theta$

$\dot \theta = \left(\frac{\dot y \cdot x - y\cdot \dot x}{x^{2}} \right)\cdot \left(\frac{x^{2}}{x^{2}+y^{2}} \right)$

$\dot \theta = \frac{\dot y \cdot x - y\cdot \dot x}{x^{2}+y^{2}}$

Finally,

$\dot \theta = \frac{\left(900\,\frac{ft}{s} \right)\cdot (4000\,ft)-(3000\,ft)\cdot \left(0\,\frac{ft}{s} \right)}{(4000\,ft)^{2}+(3000\,ft)^{2}}$

$\dot \theta = 0.144\,\frac{rad}{s}$

$\dot \theta = 8.251\,\frac{deg}{s}$

3 0

3 years ago