Answer: 27 Remainder 11
Step-by-step explanation: hope this helps you
Answer:
its the first one
Step-by-step explanation:
Ive had this question before
The ODE appears to be
It's separable; we can write
and integrating both sides yields
Let <em>x</em> be the smallest of the three integers. Then the next two are <em>x</em> + 2 and <em>x</em> + 4.
• "The ratio of the smallest number to 1 less than twice the smallest number..."
This translates to
<em>x</em> / (2<em>x</em> - 1)
• "... the ratio of 3 more than the middle number to twice the largest number."
This translates to
((<em>x</em> + 2) + 3) / (2 (<em>x</em> + 4))
or, simplifying a bit,
(<em>x</em> + 5) / (2<em>x</em> + 8)
The ratioes are said to be equivalent, so
<em>x</em> / (2<em>x</em> - 1) = (<em>x</em> + 5) / (2<em>x</em> + 8)
Solve for <em>x</em> :
<em>x</em> (2<em>x</em> + 8) = (<em>x</em> + 5) (2<em>x</em> - 1)
2<em>x</em>² + 8<em>x</em> = 2<em>x</em>² + 9<em>x</em> - 5
8<em>x</em> = 9<em>x</em> - 5
-<em>x</em> = -5
<em>x</em> = 5
So the three integers are 5, 7, and 9.
Translated: How to solve a expresson.
Elevado: high
10 plus negative 2 = 8
