The position of a body moving along a coordinate line at

Mathematics

1 answer:

Elden [556K]2 years ago

3 0

Step-by-step explanation:

s=(4+6t)3/2

t=2s

t is seconds

s is meters

s=(4+6×2)3/2

=(4+12)3/2

=16×3/2

s=24m

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Joe has fraction 5 over 6 pound of bird seed. He needs fraction 1 over 3 pound to feed the birds daily. Which of the rectangle m

Semenov [28]

Since Joe has 5/6 pounds left and he only needs 1/3 pounds each day to feed the birds, therefore the number of remaining day’s worth of seed is:

days = (5/6) / (1/3) = 2.5

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Among all monthly bills from a certain credit card company, the mean amount billed was $465 and the standard deviation was $300.

Fynjy0 [20]

Answer:

0.02% probability that the average amount billed on the sample bills is greater than $500.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 465, \sigma = 300, n = 900, s = \frac{300}{\sqrt{900}} = 10$ .