Answer:
Andy basically has two stickers
Answer:
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.7787.
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 4.9 - 3.7 = 1.2.
The upper end of the interval is the sample mean added to M. So it is 4.9 + 3.7 = 8.6.
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
$92/week is the amount of money you gained from work combined with your $20/week allowance money.
92 - 20 = 72 (total money made per week subtract allowance money leaves money made from work)
Thus, you make $72/week at your part time job.
You work a total of 9 hours. (3hrs on Fri & 6hrs on Sat added together)
72/9 = 8 (total amount of money made divided by the 9 hrs you worked for - gives amount of money you make per hour)
Thus, you make $8/hr at your part time job.
A, C, D are the correct answers.
-5 is neither a whole number nor a natural number. This is because negative numbers are not included in these. Hope this helps! Let me know:)
It is either A or D, but I think it’s A