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Basile [38]
2 years ago
14

Polygon ABCDE is reflected to produce polygon. A B C D E. what is the equation for the line of reflection

Mathematics
1 answer:
KATRIN_1 [288]2 years ago
3 0
The equation for this problem is -4/6x+7=0
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Un submarino puede descender a una velocidad de –2,5 metros / segundo. Supongamos que el submarino comienza a una profundidad de
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17.5

Step-by-step explanation:

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3 years ago
4) What is the present value of $4000 received at the
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$11040

Step-by-step explanation:

first of all the question says that $4000 were earned in a year and asks for what the new vale would be after the next 3 years with a discount rate of 8%.

If 1 year=$4000,then 3 years=$12000

100%-8%=92% (this happens because there is still a remaining amount that still has a cost to it),so 12000*92%=$11040

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3 years ago
Alice takes 6 cups of flour to make 4 loaves of bread.What is the ratio of loaves to flour
tatiyna

4 loaves : 6 cups

That simplifies to 2 loaves : 3 cups

So, your ratio is 2:3

4 0
3 years ago
A sample of salary offers (in thousands of dollars) given to management majors is: 48, 51, 46, 52, 47, 48, 47, 50, 51, and 59. U
balu736 [363]

Answer:

Step-by-step explanation:

number of samples, n = 10

Mean = (48 + 51 + 46 + 52 + 47 + 48 + 47 + 50 + 51 + 59)/10 = 49.9

Standard deviation = √(summation(x - mean)/n

Summation(x - mean) = (48 - 49.9)^2 + (51 - 49.9)^2 + (46 - 49.9)^2+ (52 - 49.9)^2 + (47 - 49.9)^2 + (48 - 49.9)^2 + (47 - 49.9)^2 + (50 - 49.9)^2 + (51 - 49.9)^2 + (59- 49.9)^2 = 128.9

Standard deviation = √128.9/10 = 3.59

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 10 - 1 = 9

Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 2.262

Margin of error = 2.262 × 3.59/√10

= 2.57

the lower limit of this confidence interval is

49.9 - 2.57 = 47.33

the lower limit of this confidence interval is

49.9 + 2.57 = 52.47

So it is false

6 0
2 years ago
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