Answer:

Step-by-step explanation:
<u>Rates of Change as Derivatives</u>
If some variable V is a function of another variable r, we can compute the rate of change of one with respect to the other as the first derivative of V, or

The volume of a sphere of radius r is

The volume of the balloon is growing at a rate of
. This can be written as

We need to compute the rate of change of the radius. Note that both the volume and the radius are functions of time, so we need to use the chain rule. Differentiating the volume with respect to t, we get


solving for 

We need to find the value of r, which can be obtained by using the condition that in that exact time


Simplifying and isolating r

![\displaystyle r=\sqrt[3]{512}=8\ cm](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%5Csqrt%5B3%5D%7B512%7D%3D8%5C%20cm)
Replacing in the rate of change



Answer:
The Answer is: 2.91 x 10^6
Step-by-step explanation:
Move the decimal from the right to left and count the number of moves, stopping at the next to last number.
Given:
2,910,000
In Scientific notation:
2.91 x 10^6
Hope this helps! Have an Awesome Day!! :-)
Average rate of change refers to the slope of a function/equation.
To solve this, plug in for both x values and calculate the average, or mean.
x = 1
f(1) = 5(2)^1
= 5(2)
= 10
x = 5
f(5) = 5(2)^5
= 5(32)
= 160
Now, you calculate the average:
10 + 160 = 170
Divide by 2 and you get 85.
Answer:
2 is the opposite of-2 and -2 is the opposite of 2
Answer:
The new point is at (5, -5)
Step-by-step explanation:
When a point is being translated down, they are being subtracted on the y-value. So all you have to do is subtract 9 from 4 and we end up with -5, our new y-value.
(5, -5)