Step-by-step explanation:
a
<h2>hope it helps.</h2><h2>stay safe healthy and happy...</h2>
The steps to construct a regular hexagon inscribed in a circle using a compass and straightedge are given as follows:
1. <span>Construct a circle with its center at point H.
2. </span><span>Construct horizontal line l and point H on line l
3. </span>Label
the point of intersection of the circle and line l to the left of point
H, point J, and label the point of intersection of the circle and line l
to the right of point H, point K.<span>
4. Construct
a circle with its center at point J and having radius HJ .
Construct a circle with its center at point K having radius HJ
5. </span><span>Label
the point of intersection of circles H and J that lies above line l,
point M, and the point of their intersection that lies below line l,
point N. Label the point of intersection of circles H and K that lies
above line l, point O, and the point of their intersection that lies
below line l, point P.
6. </span><span>Construct and JM⎯⎯⎯⎯⎯, MO⎯⎯⎯⎯⎯⎯⎯, OK⎯⎯⎯⎯⎯⎯⎯, KP⎯⎯⎯⎯⎯, PN⎯⎯⎯⎯⎯⎯, and NJ⎯⎯⎯⎯⎯ to complete regular hexagon JMOKPN .</span>
Given that Joseph has 24 cousins, and he has 6 more females than males, the number of females will be obtained as follows;
suppose he had x males, number of females will be x+6.
The total will be:
x+(x+6)=24
x+x+6=24
2x+6=24
2x=24-6
2x=18
x=18/2
x=9
thus the number of male cousins is 9, the number of female cousins will be 9+6=15
We therefore conclude that he has 9 male cousins and 15 female cousins
The answer is a=0. I hope I helped
