Answer:
Option D is correct .i.e., Vertical translation down 9 units
Step-by-step explanation:
Given Function is y = cosec x - 9
Here basic function or parent function is y = cosec x
1. When constant ' a ' is added to to parent function or basic function then the function is translated vertically upward by a units.
2. When constant ' a ' is subtracted from parent function or basic function then the function is translated vertically downward by a units.
Therefore, Option D is correct .i.e., Vertical translation down 9 units
Answer:
Step-by-step explanation:
From the graph <em>f</em>(-2) = 0
g(-2) = -3(-2) + 2
= 6 + 2 = 8.
So f(-2) is less than g(-2).
2. From the graph the y-intercept of f(x) = 8.
To find the y-intercept of g(x) solve y = -3x +2 when x = 0:
y = -3(0) + 2 = 2.
So f(x) has a greater y-intercept than g().
These questions can be daunting at first, but they're pretty simple to solve.
First, we need to establish a common denominator. We have 2 / 3, 1 / 4, and
-4 / 3. The least common denominator we can get is by multiplying 4 and 3 together to get 12. So we will change the denominator as follows;
2 / 3, 1 / 4, -4 / 3 = 8 / 12, 3 / 12, -16 / 12
Now we can put these back into the equation.
8/12x + 3/12 = -16/12
8x + 3 = -16
It's simple math from here on out, but I'll show the process. What we can basically do now is take away the denominator because it doesn't matter now that it's common.
Subtract 3 from both sides. Now we have 8x = -19
Dividing by 8 on both sides of the equation will get you your answer.
x = -19/8
Hope this helps!
Answer:
Its C
Step-by-step explanation:
It is 6 because there are 6 dots on the outer circle and those are the valence electrons. Also I just did it on Edge. Hope this helps.
Answer:
We want to find:
![\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%5Csqrt%5Bn%5D%7Bn%21%7D%20%7D%7Bn%7D)
Here we can use Stirling's approximation, which says that for large values of n, we get:
Because here we are taking the limit when n tends to infinity, we can use this approximation.
Then we get.
![\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%5Csqrt%5Bn%5D%7Bn%21%7D%20%7D%7Bn%7D%20%3D%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%5Csqrt%5Bn%5D%7B%5Csqrt%7B2%2A%5Cpi%2An%7D%20%2A%28%5Cfrac%7Bn%7D%7Be%7D%20%29%5En%7D%20%7D%7Bn%7D%20%3D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7Bn%7D%7Be%2An%7D%20%2A%5Csqrt%5B2%2An%5D%7B2%2A%5Cpi%2An%7D)
Now we can just simplify this, so we get:
![\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B1%7D%7Be%7D%20%2A%5Csqrt%5B2%2An%5D%7B2%2A%5Cpi%2An%7D%20%5C%5C)
And we can rewrite it as:
The important part here is the exponent, as n tends to infinite, the exponent tends to zero.
Thus:
