Answer:
x= 6
∠FGT = 55
∠GFE = 65
Step-by-step explanation:
<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection )
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = ![\frac{\text { number of good coils }}{\text { total number of coils }}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7B%20number%20of%20good%20coils%20%7D%7D%7B%5Ctext%20%7B%20total%20number%20of%20coils%20%7D%7D)
Hence, p(getting 2 good coil for two selection) = ![\frac{88}{100} \times \frac{88}{100} =\bold{0.7744}](https://tex.z-dn.net/?f=%5Cfrac%7B88%7D%7B100%7D%20%5Ctimes%20%5Cfrac%7B88%7D%7B100%7D%20%3D%5Cbold%7B0.7744%7D)
Step-by-step explanation:
here the answers is it helpful