En una ciudad a las 6:00am la temperatura era de 2°C. A lo largo del dia, la temperatura tuvo las siguientes variaciones:

How to solve ((-9)×(-5)-9)÷(-12)

andreyandreev [35.5K]

Answer:

-3

Step-by-step explanation:

Simplify the following:

(-9 (-5) - 9)/(-12)

-9 (-5) = 45:

(45 - 9)/(-12)

| 3 | 15

| 4 | 5

- | | 9

| 3 | 6:

36/(-12)

The gcd of 36 and -12 is 12, so 36/(-12) = (12×3)/(12 (-1)) = 12/12×3/(-1) = 3/(-1):

3/(-1)

Multiply numerator and denominator of 3/(-1) by -1:

Answer: -3

3 0

3 years ago

Need help on number 3! Ik the answer for number 4 only 3!!!

NeX [460]

1 degree is the answer

5 0

3 years ago

Can someone please help me

dusya [7]

$-\frac{1}{3}m+2 = -1 =>NO\\-2(-4m-6.4) = 44.8 => YES\\8m-5-2m +1 = 20 =>YES\\7m+6 = 9m-2 => YES$

Step-by-step explanation:

First of all, we will find the solution of the given equation

So,

Given equation is:

$3m = 36-6m$

Adding 6m on both sides

$3m+6m = 36-6m+6m\\9m = 36$

Dividing both sides by 9

$\frac{9m}{9} = \frac{36}{9}\\m = 4$

In order to check, if the solution is the solution of given options, we will put the solution in the equation, if both sides of equations are equal then the solution belongs to the equation.

So,

For $-\frac{1}{3}m+2 = -1$

Putting m=4

$\frac{-1}{3}(4)+2 = -1\\\frac{-4}{3}+2 = -1\\\frac{-4+6}{3} = -1\\-\frac{2}{3} \neq -1$

For $-2(-4m-6.4) = 44.8$

Putting m=4

$-2[-4(4)-6.4]=44.8\\-2(-16-6.4) = 44.8\\-2(-22.4) = 44.8\\44.8 = 44.8$

For $8m-5-2m +1 = 20$

Putting m=4

$8m-5-2m +1 = 20\\6m-4 = 20\\6(4) -4 = 20\\24-4 = 20\\20 = 20$

for $7m+6 = 9m-2$

Putting m = 4

$7(4) +6 = 9(4) - 2\\28+6 =36-2\\34=34$

Keywords: Equations, linear equation

Learn more about linear equation at:

#LearnwithBrainly

8 0

4 years ago

Anita's, a fast-food chain specializing in hot dogs and garlic fries, keeps track of the proportion of its customers who decide

Nady [450]

Using the binomial distribution, it is found that there is a 0.1755 = 17.55% probability that, in a random sample of 5 customers at Anita's, exactly 4 order their food to go.

For each customer, there are only two possible outcomes, either they order their food to go, or they do not. The orders of each customer are independent of other customers, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

52% of its customers order their food to go, hence $p = 0.52$ .

Random sample of 5 customers, hence $n = 5$ .

The probability that exactly 4 order their food to go is P(X = 4), hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.52)^{4}.(0.48)^{1} = 0.1755$

0.1755 = 17.55% probability that, in a random sample of 5 customers at Anita's, exactly 4 order their food to go.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

5 0

2 years ago

Select all of the true statements about the standard deviation of a quantitative variable. The standard deviation of a set of va

Pepsi [2]

Answer:

The standard deviation of a set of values is equal to 0 if and only if all of the values are the same; The standard deviation of a group of values is a measure of how far the values are from the mean; Standard deviation is never negative.

Step-by-step explanation:

Standard deviation is the distance, on average, that each point is from the mean. The only way this value can be zero is if every value is the same as the mean, making all of the data values the same.

Since standard deviation is the square root of the variance, standard deviation is never negative.

Since the standard deviation is a measure of spread from the mean, which is not resistant to outliers, the standard deviation itself is not resistant to outliers.

Changing the units of a set of values involves multiplying by a constant. For example, changing from feet to inches involves multiplying each data value by 12. When we do this, the standard deviation will also be multiplied by the same constant.

For a set of values with mean of 0 and a standard deviation that is not 0, removing a data point with a value of 0 will have an effect on the standard deviation. For example, the data set 3, 2, 1, 0, -1, -2 -3 has a mean of 0. The standard deviation of the set is 2. Removing the data point 0 increases the standard deviation to about 2.2.

7 0

3 years ago