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3 years ago

How to solve ((-9)×(-5)-9)÷(-12)

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

3 0

Answer:

-3

Step-by-step explanation:

Simplify the following:

(-9 (-5) - 9)/(-12)

-9 (-5) = 45:

(45 - 9)/(-12)

| 3 | 15

| 4 | 5

- | | 9

| 3 | 6:

36/(-12)

The gcd of 36 and -12 is 12, so 36/(-12) = (12×3)/(12 (-1)) = 12/12×3/(-1) = 3/(-1):

3/(-1)

Multiply numerator and denominator of 3/(-1) by -1:

Answer: -3

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Step-by-step explanation:

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2*3=6

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3 years ago

From the point on the ground 500 ft from the base of a building, it is observed that the angle of elevation to the top of the bu

AveGali [126]

Answer:

building: 222.61 ft
flagpole: 32.15 ft

Step-by-step explanation:

The tangent function of an angle in a right triangle is the ratio of the opposite side to the adjacent side. Here, the adjacent side is 500 ft, so we have ...

tan(24°) = (building height)/(500 ft)

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3 years ago

Quadrilateral ABCD has vertices A (-3, 0), B (2, 4), C (3, 1), and D (-4, -3). Calculate the perimeter of the quadrilateral. Rou

Andru [333]

Answer:

Perimeter of the Quadrilateral=20.78

Step-by-step explanation:

Perimeter of the Quadrilateral= AB+BC+CD+AD

Finding the sides of the quadrilateral using the Distance formula:

A(-3,0), B(2,4), C(3,1) and D(-4,-3)

$AB=\sqrt{(2-(-3))^2+(4-0)^2}\\\\ =\sqrt{(2+3)^2+4^2}\\\\ =\sqrt{5^2+4^2} \\\\=\sqrt{25+16}\\\\ =\sqrt{41}\\$

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BC=

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$AD=\sqrt{(-4-(-3))^2+(-3-0)^2} \\\\=\sqrt{(-4+3)^2+(-3)^2} \\\\=\sqrt{(-1)^2+(-3)^2} \\\\=\sqrt{1+9}\\\\=\sqrt{10} \\\\ =3.16$

Perimeter of the quadrilateral= AB+BC+CD+AD

=6.40+3.16+8.06+3.16

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