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tiny-mole [99]
3 years ago
11

what is the volume of a sphere with a radius of "60.5" Ft, Rounded to the nearest tenth of a cubic foot?​

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

volume = 927,587.2ft^3

Step-by-step explanation:

The equation to find the volume of a sphere is as follows:

volume = \frac{4}{3}\pi r^3

We have a radius of 60.5ft, let's plug this into the equation and solve:

volume = \frac{4}{3} \pi (60.5)^3 \\volume = 927,587.17\\volume = 927,587.2

Therefore, the volume of a sphere with a radius of 60.5ft is 927,587.2ft^3.

<em>Hope this helps!!</em>

<em>- Kay :)</em>

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iren [92.7K]

Answer:

335\:\text{ft}

Step-by-step explanation:

The circumference of a circle is given by C=2\pi r, where r is the radius of the circle. Therefore, we can set up the following equation and solve:

2\pi r=2107,\\r=\frac{2107}{2\pi},\\r\approx \boxed{335\:\text{ft}} (rounded to the nearest foot).

7 0
3 years ago
A coffee machine dispenses normally distributed amounts of coffee with a mean of 12 ounces and a standard deviation of 0.2 ounce
NemiM [27]

Answer:

0.9332 = 93.32% probability that the mean of the sample will be less than 12.1 ounces.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 12 ounces and a standard deviation of 0.2 ounces.

This means that \mu = 12, \sigma = 0.2

Sample of 9:

This means that n = 9, s = \frac{0.2}{\sqrt{9}}

Find the probability that the mean of the sample will be less than 12.1 ounces.

This is the pvalue of Z when X = 12.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{12.1 - 12}{\frac{0.2}{\sqrt{9}}}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

0.9332 = 93.32% probability that the mean of the sample will be less than 12.1 ounces.

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3 years ago
five friends by a package of 12 cookies and want to share them equally each friend will get 1/5 of the cookies how much will eac
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Answer:

2.4 cookies

Step-by-step explanation:

Just divide

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​ g(x)=−20−3x h(x)=( 2 1 ​ ) x ​ Evaluate. (g\circ h) (-2)=(g∘h)(−2)=left parenthesis, g, circle, h, right parenthesis, left par
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Step-by-step explanation:

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3 years ago
Shapes A and B are similar.
kari74 [83]

The scale factor from A to B is 5/3 and the value of r is 33/5

<h3>The scale factor from A to B</h3>

From the figure, we have the following corresponding sides

A : B = 5 : 3

Express as fraction

B/A = 3/5

This means that, the scale factor from A to B is 5/3

<h3>The value of r</h3>

From the figure, we have the following corresponding sides

A : B = 11 : r

Express as fraction

B/A = r/11

Recall that:

B/A = 3/5

So, we have:

3/5 = r/11

Multiply by 11

r = 33/5

Hence, the value of r is 33/5

Read more about similar shapes at:

brainly.com/question/14285697

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