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Stells [14]
4 years ago
15

18 is what percent of 20?

Mathematics
2 answers:
velikii [3]4 years ago
5 0

divide it

18/20 = 0.9

18 is 90% of 20

Ne4ueva [31]4 years ago
4 0
Theeeeeee anweeeer isssss

90%

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Write an inequality for the following.<br> Jackie spent no more than $40 on a video
ANEK [815]

Answer:

x ≥ $40

Step-by-step explanation:

Jackie didn't spend more than $40 on a video.

x ≥ $40

7 0
3 years ago
Solve for m:<br> 2r= m/r <br><br><br> m = 2r<br> m = 2r squared by 2<br> m=r<br> m = 2
Bad White [126]
Solution

Switch sides so that m is on the left side

m/r = 2r

Them multiply both sides by r

mr/r = 2rr

Now simplify the equation

m = 2r^2

Therefore the equation evaluates to
m = 2r squared by 2
6 0
3 years ago
Need help with this problem for my cousin
yKpoI14uk [10]
You have separated the figure into three (3) parts. There are two squares (or rectangles on the bottom. Subtract 5 from 8 to find out the length of the side (right side). 8-5=3. Then subtract 3 from 8 (8-3=5). The new length is 5 ft. 5 multiplied by 5 is the area of one of the squares on the bottom (25 ft. squared). Multiply that by two to find the area of both the squares on the bottom (50 ft. squared).

There's also a rectangle on the top. The base is 15 ft. and the height is 3 ft. Remember that you subtracted 5 from 8 to find out the area of the two bottom squares. 15 multiplied by 3 is 45 (ft.)

Add 45 to 50 to get the area of the entire figure. (45+50=95 or 95 ft. squared).

95 ft. squared is the area of the entire figure. Hope this helped you.
3 0
3 years ago
Is 3y^2-2y already simplified
geniusboy [140]
Yes it is already simplified because there is nothing else that you are able to do to it.
4 0
3 years ago
Read 2 more answers
Determining Whether a Difference Is Statistically
SCORPION-xisa [38]

Using the z-distribution, it is found that:

  • The 95% confidence interval is of -1.38 to 1.38.
  • The value of the sample mean difference is of 1.74, which falls outside the 95% confidence interval.

<h3>What is the z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm zs

In which:

  • \overline{x} is the difference between the population means.
  • s is the standard error.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The estimate and the standard error are given by:

\overline{x} = 0, s = 0.69

Hence the bounds of the interval are given by:

\overline{x} - zs = 0 - 1.96(0.69) = -1.38

\overline{x} + zs = 0 + 1.96(0.69) = 1.38

1.74 is outside the interval, hence:

  • The 95% confidence interval is of -1.38 to 1.38.
  • The value of the sample mean difference is of 1.74, which falls outside the 95% confidence interval.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ2

6 0
3 years ago
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