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olga55 [171]
3 years ago
14

Which expressions are equivalent to 74-x-3)? Select two options.

Mathematics
2 answers:
Bezzdna [24]3 years ago
5 0

Answer:

B and C are the answers. I hope its helpful

Burka [1]3 years ago
3 0

Answer:

<h2>A,E</h2>

Step-by-step explanation:

Edge 2021

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Please answer it now in two minutes
Degger [83]

Answer:

47

Step-by-step explanation:

360-62-75-26-9=188

188/4=47

4 0
3 years ago
Two pieces of fabric
Bess [88]

Answer:

<h2>             487/8 inches      </h2>

Step-by-step explanation:

\left(\dfrac{143}{4}-\dfrac38\right)+\left(\dfrac{207}{8}-\dfrac38\right)=\dfrac{286}{8}-\dfrac38+\dfrac{204}{8}=\dfrac{283}{8}+\dfrac{204}{8}=\dfrac{487}{8}

6 0
3 years ago
Point A is in Quadrant II.
Digiron [165]

Answer:

First quadrant

Step-by-step explanation:

A is reflected to the right over the x-axis

7 0
2 years ago
Lucy spends 4 hours a week babysitting. Her sister Lily spends seven eighths as much time babysitting. Does Lily babysit for mor
olganol [36]

Answer:

Lily babysit for <u>less than 4 hours</u>.

Step-by-step explanation:

Given:

Lucy spends in a week babysitting for 4 hours.

Lily spends seven-eighths of 4 hours.

Now, to find whether Lily babysit for more than 4 hours or less than that.

Number of hours Lucy babysit = 4 hours.

So, to get the hours Lily babysit:

\frac{7}{8}\ of\ 4\ hours.

=\frac{7}{8}\times 4\\\\=\frac{28}{8} \\\\

<em>On simplifying we get:</em>

=\frac{7}{2} \\\\=3\frac{1}{2}\ hours.

<u><em>Thus, Lily spends </em></u>3\frac{1}{2}\ hours<u><em>  for babysitting which is less than 4 hours.</em></u>

Therefore, Lily babysit for less than 4 hours.

4 0
4 years ago
The lines 2x=ky+2 and (k+1)x=6y-3 have same gradient. Find possible values of k
faust18 [17]

Answer:

k = 3 or k = -4

(Anyone can correct me if I'm wrong)

Step-by-step explanation:

2x=ky+2\to\ eq1\\(k+1)x=6y-3\to\ eq2\\$Change to this form: $y=mx+c\\ky=2x-2\\y=\frac{2x-2}{k}\\$gradient of eq1: $\frac{2}{k}\\6y=(k+1)x+3\\y=\frac{(k+1)x+3}{6}\\y=\frac{k+1}{6} x+\frac{3}{6}\\y= \frac{k+1}{6} x+\frac{1}{2}\\$gradient of eq1: $\frac{k+1}{6}\\$Since gradient, m, is the same for both lines,$\\\frac{2}{k}=\frac{k+1}{6}\\12=k^{2}+k\\k^{2}+k-12=0\\(k-3)(k+4)=0\\k=3 $ or $ k=-4

6 0
3 years ago
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