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3 years ago

11

Jamal spent 1 1/2 hours studying for his science test ruby studied for 1/3 the amount of time that Jamal studied what fraction o

f an hour did ruby spend studying

1 answer:

Maksim231197 [3]3 years ago

7 0

Answer:

3/6

Step-by-step explanation:

hi please get me the answer

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Write an equation for the situation Kevin's paycheck was $175. He gets paid 6 dollars an hour plus an additional 17 dollars in t

MrRa [10]

Answer: 6h + 17 = 175

8 0

3 years ago

Without a calculator how would you solve this?

mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

$\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6$

$=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}$

$\bigstar\ (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}$

$\bigstar\ \bigstar\ (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}$

$\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702$

$\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6$

$0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0$

$\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0$

$\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702$

8 0

3 years ago

What is the smallest positive difference between two fractions if the denominators are 3 and 5?

Karolina [17]

Answer:

the answer would be 15

Step-by-step explanation:

1/3 x 1/5 =1/15

8 0

3 years ago

Read 2 more answers

Factorise. X^5+X^4+1.

suter [353]

Answer:

Answer

5.0/5

2

poojamaurya21

Virtuoso

133 answers

14.9K people helped

Answer:

): "x2" was replaced by "x^2". 4 more similar replacement(s).

Step by step solution :

Step 1 :

Step 2 :

Pulling out like terms :

2.1 Pull out like factors :

x6 - x5 + x4 - x3 + x2 - x =

x • (x5 - x4 + x3 - x2 + x - 1)

2.2 Factor x5 - x4 + x3 - x2 + x - 1

Try to factor this 6-term polynomial into (2-term) • (3-term)

Begin by splitting the 6-term into two 3-term polynomials:

-x2 + x - 1 and x5 - x4 + x3

Next simplify each 3-term polynomial by pulling out like terms:

-1 • (x2 - x + 1) and x3 • (x2 - x + 1)

Note that the two simplified polynomials have x2 - x + 1 in common

Now adding the two simplified polynomials we get

(x3 - 1) • (x2 - x + 1)

3 0

3 years ago

A homeowner's backyard is a rectangle with width 18 yards long and length 16 yards long. They plan to put in a square pool with

Ugo [173]

Answer:

Step-by-step explanation:

Given the dimension of the homeowner's backyard to be width 18 yards long and length 16 yards long, the area of the rectangular backyard id expreesed as;

Area of rectangle = Length * Width

Area of the rectangular backyard = 18yards * 16yards

Area of the rectangular backyard = 288yards²

If they plan to put in a square pool with side length 5 yards long in the backyard, the area of the pool = 5yd*5yd = 25yd²

The remaining area that will contain the tiles = Area of the rectangular backyard - area of the pool

The remaining area that will contain the tiles = 288yd² - 25yd² = 263yd²

<em>Note that we cannot determine the amount of tiles they need to buy since we are not given the dimension of each tile to use</em>. The area needed for the tiles for the rest of the backyard is therefore 263yd².

Amount of tiles needed to buy can be expressed as 263/dimension of a tile.

4 0

3 years ago