What model? also it would be 1/2 and 1/3
Probably d as the the temperature outside is unpredictable and the we know the time is always going up
Answer:
x = 57/28
y = -95/84
z = 97/168
Step-by-step explanation:
Use the application in the next link: https://www.zweigmedia.com/RealWorld/tutorialsf1/scriptpivotold.html
Start with the expanded array:
![\left[\begin{array}{cccc}1&5&8&1\\3&2&2&5\\-2&-7&2&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C3%262%262%265%5C%5C-2%26-7%262%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
then using the tool provided, make row operations until you find the solution:
r2 = r2-3r1
![\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\-2&-7&2&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C0%26-13%26-22%262%5C%5C-2%26-7%262%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r3 = r3+2r1
![\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\0&3&18&7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C0%26-13%26-22%262%5C%5C0%263%2618%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r2 = r2*(-1/13)
![\left[\begin{array}{cccc}1&5&8&1\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%263%2618%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r1 = r1- r2*5
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%263%2618%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r3 = r3+ r2*-3
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&168/13&97/13\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%260%26168%2F13%2697%2F13%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r3 = r3*13/168
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&1&97/168\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%260%261%2697%2F168%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r2 = r2- r3*22/13
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%260%26-95%2F84%5C%5C0%260%261%2697%2F168%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r2 = r2+ r3*6/13
![\left[\begin{array}{cccc}1&0&0&57/28\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%2657%2F28%5C%5C0%261%260%26-95%2F84%5C%5C0%260%261%2697%2F168%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Here you have a reduced array an therefore the answers to each variable are on each row:
![\left[\begin{array}{c}x\\y\\z\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D)
ANSWER

EXPLANATION
The given expression is

We remove the perfect squares under the radical sign.

We can now take square root of the perfect squares and simplify them further.

This simplifies to:

This further simplifies to:

You only flip the inequality sign when you multiply or divide both sides by a negative number.
================================================
Problem 1

The inequality sign flip happens because we divided both sides by -8.
The graph will have a closed circle at 4 with shading to the left.
Three solutions are x = 0, x = 1, x = 2. You can pick any three numbers you want as long as they are 4 or smaller.
================================================
Problem 2

The graph will have an open circle at 13/3 = 4&1/3 = 4.333 approx. The shading is to the left. No inequality sign flip happens because we divided both sides by a positive number.
Your choice of three solutions is correct. You can pick anything smaller than 4.3333
================================================
Problem 3

The solution set is any value 3 or larger. Three solutions are x = 5, x = 6 and x = 7.
The graph has a closed circle at 3 on the number line. The shading is to the right.