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julia-pushkina [17]
2 years ago
13

Find the volume of the composite solid.

Mathematics
1 answer:
OLEGan [10]2 years ago
4 0

Here's the solution,

the volume of the given figure is :

=》

volume \:  \: of \:  \: (pyramid \:  + rectangular \:  \: prism)

volume of pyramid :

=》

\dfrac{l \times b \times h}{3}

=》

\dfrac{4 \times 5 \times 6}{3}

=》

\dfrac{120}{3}

=》

40

volume of pyramid = 40 cm³

now, volume of rectangular prism :

=》

l \times b \times h

=》

4 \times 5 \times 2

=》

40

volume of rectangular prism = 40 cm³

volume of composite figure = 40 + 40

=》80 cm³

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Sindrei [870]

Answer:

where is the diagram

4 0
3 years ago
Solve 8(1/4×+3/4)-3=17
stepladder [879]
8(1/4x + 3/4) -3 =17

First distribute which results in (8/4x + 24/4)-3 =17.
Now just simply simplify it into (2x+6)-3 =17
Then you combine like term : 2x+3 =17

Subtract 3 on both sides : 2x=14

Finally divide 2 on both sides to isolate x: x=7
7 0
3 years ago
Read 2 more answers
Q‒1. [5×4 marks] a) How many three-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6? (150) b) How many three-
amid [387]

Answer:

a) 294

b) 180

c) 75

d) 174

e) 105

Step-by-step explanation:

I assume that for each problem, the first digit can't be 0.

a) There are 6 digits that can be first, 7 digits that can be second, and 7 digits that can be third.

6×7×7 = 294

b) This time, no digit can be used twice, so there are 6 digits that can be first, 6 digits that can be second, and 5 digits that can be third.

6×6×5 = 180

c) Again, each digit can only be used once, but this time, the last digit must be odd.

If only the last digit is odd, there are 3×3×3 = 27 possible numbers.

If the first and last digits are odd, there are 3×4×2 = 24 possible numbers.

If the second and last digits are odd, there are 3×3×2 = 18 possible numbers.

If all three digits are odd, there are 3×2×1 = 6 possible numbers.

The total is 27 + 24 + 18 + 6 = 75.

d) If the first digit is 3, and the second digit is 3, there are 1×1×6 = 6 possible numbers.

If the first digit is 3, and the second digit is greater than 3, there are 1×3×7 = 21 possible numbers.

If the first digit is greater than 3, there are 3×7×7 = 147 numbers.

The total is 6 + 21 + 147 = 174.

e) If the first digit is 3, and the second digit is greater than 3, then there are 1×3×5 = 15 possible numbers.

If the second digit is greater than 3, there are 3×6×5 = 90 possible numbers.

The total is 15 + 90 = 105.

6 0
3 years ago
Help me answer this thanks
zysi [14]
It should be 77 because 180-55-48=77 and I took the test
5 0
3 years ago
Read 2 more answers
WILL GET BRAINLIEST!!!! I NEED IT BY TODAY!!! <br> NO FAKE ANSWERS!!!!
jarptica [38.1K]

Answer:

am sure its d please mark brainliest

6 0
3 years ago
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