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2 years ago

Using the given points, determine Δy. (-3, -5) and (0, 10) Δy = 3 Δy = 5 Δy = 13 Δy = 15

Mathematics

1 answer:

juin [17]2 years ago

4 0

Answer:

Δy=(10+5)=15

Step-by-step explanation:

we know that

The formula to calculate Δy between two points is equal to

Δy=(y2-y1)

we have

(-3, -5) and (0, 10)

substitute the values

Δy=(10-(-5))=(10+5)=15

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1 year ago

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Mariulka [41]

Given:

The equation is,

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Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

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$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

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$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

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$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

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Step-by-step explanation:

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3 years ago

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