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omeli [17]
3 years ago
11

Construct a square inscribed in a circle using the construction tool. Insert a screenshot of the

Mathematics
2 answers:
slava [35]3 years ago
7 0

Answer:

yo that helps out alot

Step-by-step explanation:

Scorpion4ik [409]3 years ago
6 0

Answer:

the answer is down below the screenshot

Step-by-step explanation:

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What is the equation of a vertical line passing through (−5, −2)? a: x = −5 b: x = −7 c: y = −3 d: y = −2
drek231 [11]

The answer is

A : x=-5

6 0
3 years ago
The graphs of three functions are shown.
satela [25.4K]

Answer:

  • The square root and quadratic function share a y-intercept.
  • The range of the square root and absolute value function are the same.

Step-by-step explanation:

Y-intercepts are the same when the curves meet the y-axis at the same point. That is true of the root and quadratic functions.

X-intercepts are the same when the curves meet the x-axis at the same point. None of these functions share an x-intercept.

The ranges of the functions are the same when they have the same vertical extent. The range of the quadratic is different from the range of the other two functions.

The absolute value and root functions have the same minimum (lower end of their range). That is the same as the maximum of the quadratic function.

__

The statements that match the graphs are ...

  • The square root and quadratic function share a y-intercept.
  • The range of the square root and absolute value function are the same.
7 0
3 years ago
Read 2 more answers
What is the exact volume of the sphere? 36.868π m³ 94.46π m³ 147.456π m³ 463.01π m³ Sphere with dotted line extending from middl
Bezzdna [24]
80% sure it b 94.46π m³
3 0
3 years ago
Read 2 more answers
Help, Help, Please
Lesechka [4]

Answer:

θ = \frac{\pi }{3} (60° )

Step-by-step explanation:

Using the identity

sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x

Given

cos²θ - sin²θ = 2 - 5cosθ

cos²θ - (1 - cos²θ) = 2 - 5cosθ

cos²θ - 1 + cos²θ = 2 - 5cosθ

2cos²θ - 1 = 2 - 5cosθ ( subtract 2 - 5cosθ from both sides )

2cos²θ + 5cosθ - 3 = 0 ← in standard form

(cosθ + 3)(2cosθ - 1) = 0 ← in factored form

Equate each factor to zero and solve for θ

cosθ + 3 = 0

cosθ = - 3 ← not possible as - 1 ≤ cosθ  ≤ 1

2cosθ - 1 = 0

cosθ = \frac{1}{2} , so

θ = cos^{-1} (\frac{1}{2} ) = \frac{\pi }{3} ( or 60° )

8 0
3 years ago
Read 2 more answers
Historically, the proportion of students entering a university who finished in 4 years or less was 63%. To test whether this pro
Neporo4naja [7]

Answer:

z(c)  = - 1,64

We reject the null hypothesis

Step-by-step explanation:

We need to solve a proportion test ( one tail-test ) left test

Normal distribution

p₀ = 63 %

proportion size  p = 51 %

sample size  n = 114

At 5% level of significance   α = 0,05, and with this value we find in z- table z score of z(c) = 1,64  ( critical value )

Test of proportion:

H₀     Null Hypothesis                        p = p₀

Hₐ    Alternate Hypothesis                p < p₀

We now compute z(s) as:

z(s) =  ( p - p₀ ) / √ p₀q₀/n

z(s) =( 0,51 - 0,63) / √0,63*0,37/114

z(s) =  - 0,12 / 0,045

z(s) = - 2,66

We compare z(s) and z(c)

z(s) < z(c)      - 2,66 < -1,64

Therefore as z(s) < z(c)  z(s) is in the rejection zone we reject the null hypothesis

5 0
4 years ago
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