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3 years ago

What is 10 15/4 equivalent to

Mathematics

1 answer:

GrogVix [38]3 years ago

7 0

Answer:

(10×4 +15) / 4

(40+15) / 4

55/4

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A cyclist rode at an average speed of 15 mph for 30 miles. How long was the ride? Question 6 options: 0.5 hours 1 hour 2 hours 3

Rus_ich [418]

Answer:

2 hours

Step-by-step explanation:

using the relationship

distance = speed × time, then

time = $\frac{distance}{speed}$ = $\frac{30}{15}$ = 2 hours

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3 years ago

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In which quadrant would point (-4.5, -4.5) be located

Leviafan [203]

It’s the 3rd one.. . i’m

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3 years ago

-2x-1 is less than or equal to 5 how can you solve it

aniked [119]

Answer

x ≥ -2

Explanation
The inequalities are solve the same way as algebra. This would be solve as follows.
-2x-1≤5
-2x≤5+1
-2x≤4

Divide both sides of the inequality by -2. This will change the sign from ≤ to ≥.

(-2x)/(-2) ≤ 4/(-2)
x ≥ -2

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3 years ago

(-625)+925+100+(-200)

lapo4ka [179]

Answer:

200

Step-by-step explanation:

-625 + 925 = 300

300 +100 = 400

400 +(-200) = 400-200

400-200 = 200

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4 years ago

Need an answer here please

RideAnS [48]

Answer:

Option 4: A ║B

Step-by-step explanation:

Given the following statements:

$\displaystyle\mathsf{\overline{X}}$ is ⊥ $\displaystyle\mathsf{\overline{A}}$

$\displaystyle\mathsf{\overline{X}}$ is ⊥ $\displaystyle\mathsf{\overline{B}}$

We can apply the Lines Perpendicular to a Transversal Theorem, which states that if two lines intersect and are perpendicular to that same transversal, then those two lines are parallel.

In the given conditional statement, $\displaystyle\mathsf{\overline{X}}$ ⊥ $\displaystyle\mathsf{\overline{A}}$ and $\displaystyle\mathsf{\overline{X}}$ ⊥ $\displaystyle\mathsf{\overline{B}}$ , line $\displaystyle\mathsf{\overline{X}}$ is the transversal that cuts through both lines $\displaystyle\mathsf{\overline{A}}$ and $\displaystyle\mathsf{\overline{B}}$ .

Therefore, lines $\displaystyle\mathsf{\overline{A}}$ and $\displaystyle\mathsf{\overline{B}}$ are perpendicular to line $\displaystyle\mathsf{\overline{X}}$ . Hence, by the Lines Perpendicular to a Transversal Theorem, $\displaystyle\mathsf{\overline{A}}$ ║ $\displaystyle\mathsf{\overline{B}}$ .

4 0

3 years ago

What is 10 15/4 equivalent to​

What is 10 15/4 equivalent to