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miv72 [106K]
2 years ago
5

Given that polygon PQRS≅ polygon LMNO, identify the congruent corresponding part for PQ

Mathematics
1 answer:
vampirchik [111]2 years ago
6 0

Answer:

LM

Step-by-step explanation:

Usually these problems would already be in order, so since PQ are the first 2 letters of polygon PQRS, then for LMNO, it's LM.

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What is the domain and range of the relation [(1, -8), (-7,8), (-3, 7). (-3, -5]?​
Nadusha1986 [10]

Step-by-step explanation:

domain = {-7, -3, 1}

range ={-8, -5, 7, 8}

6 0
3 years ago
please help me answer this please! I need it fast I need all three of these answers and please show your work! Thank you very mu
mars1129 [50]
15. In a similar figure the sides are proportional. So you have to say which ratio of sides is also proportional or which sides are equal to the fraction 44/35.2

it would be c because :
44/35.2 = 132/105.6

16. same thing with similar triangles. if the length of sides are similar then so is perimeter. So so we find the ratio of the side lengths. We we know sq is 6 and qt is 24. So st is 30. So so the line st and sq are matching and similar so we compare their lengths and get a ratio
sq * x = st
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So so the perimeter is 5 times more than small triangle so
5 * 20 = 100

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5 0
3 years ago
9x^2-6x+8=0 what is the fifth step in solving this equation
Simora [160]

Answer:

write the equation as a binomial

Step-by-step explanation:


8 0
3 years ago
3. Galshore of Maloat is making a journey from the island of Gont to Oranea. The distance from the two lands is 965 miles. Galsh
USPshnik [31]

Answer:

  3.  about 7.48 hours

  4.  about 1.8892 hours

Step-by-step explanation:

Both of these questions make use of the relation ...

  time = distance / speed

3. time = (965 mi)/(129 mi/h) ≈ 7.48062 h ≈ 7.48 h

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4. time = (612.1 mi)/(324 mi/h) ≈ 1.889198 h ≈ 1.8892 h

(We have rounded the time to sufficient precision so that the distance at the given speed rounds to the number given.)

3 0
3 years ago
Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
lozanna [386]

we are supposed to find

Which of these properties is enough to prove that a given parallelogram is also a Rectangle?

As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.

The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.

In a parallelogram The opposite angles and opposite sides are always equal.

Hence the correct option is

The diagonals are congruent.

3 0
4 years ago
Read 2 more answers
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