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Anon25 [30]
3 years ago
6

Determine what type of number the solutions are and how many exist for the equation 3x^2+7x+5=0

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

Two complex (imaginary) solutions.

Step-by-step explanation:

To determine the number/type of solutions for a quadratic, we can evaluate its discriminant.

The discriminant formula for a quadratic in standard form is:

\Delta=b^2-4ac

We have:

3x^2+7x+5

Hence, a=3; b=7; and c=5.

Substitute the values into our formula and evaluate. Therefore:

\Delta=(7)^2-4(3)(5) \\ =49-60\\=-11

Hence, the result is a negative value.

If:

  • The discriminant is negative, there are two, complex (imaginary) roots.
  • The discriminant is 0, there is exactly one real root.
  • The discriminant is positive, there are two, real roots.

Since our discriminant is negative, this means that for our equation, there exists two complex (imaginary) solutions.

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