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2 years ago

Question 2 of 6

Mathematics

2 answers:

Kitty [74]2 years ago

6 0

Answer:

you fist have to gather your resources

alex41 [277]2 years ago

5 0

Answer:

i guess D

because it is most important to understand the problem before going to any further step or conclusions.

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The power generated by an electrical circuit (in watts) as a function of its current ccc (in amperes) is modeled by: P(c)=-20(c-

alekssr [168]

Answer:

The current that produces maximum power is 3A

Step-by-step explanation:

Given

$P(c) = 20(c - 3)^2$

Required [Missing from the question]

The current that produces maximum power

First, we represent the function in standard form

$P(c) = 20(c - 3)^2$

$P(c) = 20(c - 3)(c - 3)$

Open bracket

$P(c) = 20(c^2 -6c+ 9)$

$P(c) = 20c^2 -120c+ 180$

The maximum value of c is:

$Max(c) = \frac{-b}{2a}$

Where:

$f(x) = ax^2 + b^2 + c$

By comparison: $P(c) = 20c^2 -120c+ 180$

$a = 20$

$b = -120$

$c = 180$

So, we have:

$Max(c) = \frac{-b}{2a}$

$Max(c) = \frac{-(-120)}{2 * 20}$

$Max(c) = \frac{120}{40}$

$Max(c) = 3$

5 0

2 years ago

6/7 plus 4/5 times 4/5

Art [367]

Answer:

1.49714285714

Step-by-step explanation:

6/7+4/5*4/5

=6/7+0.64

=1.49714285714

8 0

2 years ago

Identify the domain, range, and codomain in each graph. Then use the codomain and range to determine whether the

Dima020 [189]

Answer:

Step-by-step explanation:

Domain : Set of all possible input values (x-values) on a graph

Codomain : Set of all possible out values for the input values (y-values) on the graph

Range : Actual output values for the input values (x-values) given on the graph.

Therefore, for the given graph,

Domain : (-∞, ∞)

Codomain : (-∞, 2]

Range : (-∞, 2]

From the given graph every input value there is a image or output value.

Therefore, the given function is onto.

4 0

2 years ago

Choose the number that has the digit 5 with value thats is 10 times less than the value of the digit 5 in This number is 54,271

kondaur [170]

54,271 is the answer

8 0

3 years ago

Ms. Martinez drove 20 miles in March. She drove 5 times as many miles in March as she did in January. She drove 4 times as many

SVETLANKA909090 [29]

Answer:

825/3 = 275 which is how many miles she drove in January.

275*4= 1100 which is how many miles she drove in February.

Ms. Turner drove 1100 miles in February.

Step-by-step explanation:

3 0

2 years ago