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Tpy6a [65]
3 years ago
6

I need help with 5 and 7

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0
I can't see them all the way
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5 0
3 years ago
8x^-9+(-3x^-3y-2)(5/x^6y-2)
DaniilM [7]

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

the first step is to deal with the negative exponents, which causes numbers to go to the other side of the fraction

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

goes to

\frac{8}{x^9}+(\frac{-3}{x^3y^2})(\frac{5y^2}{x^6})

now we can simplify the multiplied terms

\frac{8}{x^9}+(\frac{-15}{x^9})

Now that we have common bases, we can add the 2 fractions together to get

\frac{-7}{x^9}

8 0
3 years ago
11) Solve the following equations, using the lines to show each step.<br><br> 4x + 5 = 2x + 7
asambeis [7]

Answer:

4x + 5 = 2x + 7

4x + 5 - 2x = 2x - 2x +7

2x + 5 = 7

2x + 5 - 5 = 7 - 5

2x = 2

2x÷2 = 2÷2

x = 1

Please Mark Brainliest

6 0
2 years ago
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