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2 years ago

Hello, Can you please answer this.

Mathematics

1 answer:

Yanka [14]2 years ago

6 0

I just wanted to remind you you’re great

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Find the value of x by filling in the blanks in the provided statement- reason solution

fgiga [73]

Answer/Step-by-step explanation:

Given:

m<MNQ = 132°

m<Q = 54°

m<P = 3x

1. m<MNQ = m<P + m<Q

Reason: exterior angle theorem of a triangle

Plug in the values

2. 132° = 3x + 54°

Reason: Substitution

3. x = 26

Reason: Algebra

132 - 54 = 3x (substraction property of equality)

78 = 3x

78/3 = x (division property of equality)

26 = x

x = 26

3 0

3 years ago

In the equation x^2+10x+24=(x+a)(x+b), b is an integer. Find algebraically all possible values of b

Vinil7 [7]

(x+4)(x+6)
(x+6)(x+4)

8 0

3 years ago

The distance from the center of a carousel to the

anzhelika [568]

Answer:

$\fbox{\begin{minipage}{3.5em}338 (ft)\end{minipage}}$

Step-by-step explanation:

The problem could be simplified as following:

Given:

The radius of a circle O is 26 feet.

Solve for:

The length of arc on circle O that measures 13 radians

Solution:

Step 1: Let's find out the correct formula to apply:

The formula to calculate the length of an arc measuring x radians on a circle with radius r feet is:

L = r*x

Step 2: Let's put the data into formula to work out the length L of arc:

L = 26*13 = 338 (ft)

=> The distance that a horse does on the outer edge travel when the carousel rotates through 13 radians: L = 338 (ft)

Hope this helps!

7 0

3 years ago

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

1 year ago

What is 1+1 * the square root of 199 and 198

torisob [31]

Answer:2.14.07

Step-by-step explanation:

4 0

2 years ago

Hello, Can you please answer this.​

Hello, Can you please answer this.