A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.
Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b
-2 = (3/4)*(12) + b
You'll get b= -11
So the equation of the parallel line intersecting the point given is y= 3/4x -11.
I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.
Answer:
f(x) = x³ − 5x² − 16x + 80
Step-by-step explanation:
The degree is 3, so there are exactly 3 zeros.
The zeros are -4, 4, and 5.
f(x) = (x + 4) (x − 4) (x − 5)
f(x) = (x² − 16) (x − 5)
f(x) = x³ − 5x² − 16x + 80
D because its more formal then the other ones.
Answer:
B. c = 2.6
Step-by-step explanation:
$13.00 / 5 = 2.6
