The diagonal crossbar would create a hypotenuse so you can use Pythagorean Theorem of a^2 + b^2 = c^2. The two '4 feet' lengths would be the legs (a and b).
So now just plug in: 4^2 + 4^2 = c^2. Simplify to 16 + 16 = c^2. Simplify again to 32 = c^2. Square root both sides to isolate the variable c. to get C = sq
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The length of one of the diagonal crossbars is feet.
So now just plug in: 4^2 + 4^2 = c^2. Simplify to 16 + 16 = c^2. Simplify again to 32 = c^2. Square root both sides to isolate the variable c. to get C = sq
The length of one of the diagonal crossbars is