Answer:
Please see attachment
Step-by-step explanation:
Please see attachment
I agree because he calculated it the right way and that is the same answer I got.
Hope I helped :)
in every die thrown 100 times a six occurs 32 times
so the probability of obtaining a die after 100 throws = 
Get into ax²+bx+c=0 form
subsitute u=x⁴
x⁸-3x⁴+2=0
(x⁴)²-3(x⁴)+2=0
u²-3u+2=0
factor
(u-2)(u-1)=0
set to zero
u-2=0
u=2
u-1=0
u=1
wait, u=x⁴
2=x⁴
![\sqrt[4]{2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D%3Dx)
1=x⁴
+/-1=x
the subsitution is u=x⁴
and the possible values for x are -1,
![\sqrt[4]{2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D%3Dx)
, and 1
Answer:
-7/25.
Step-by-step explanation:
From the given point P we see that the hypotenuse = √(3*2 + 4^2) = 5.
So cos θ = 3/5
cos 2 θ = 2 cos^2 θ - 1
= 2 * (3/5)^2 -1
= -7/25.