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Dmitrij [34]
4 years ago
10

P. John roller skates with a constant

Mathematics
1 answer:
Vitek1552 [10]4 years ago
3 0

Answer:

2 1/2 hours

Step-by-step explanation:

1. multiply 12 by 2 to get 24

2. divide 12 by 2 to get 6 mph (miles per hour)

3. Add the 6 and 24

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jo has a total of 61 dimes and quarters in her piggy bank. she has 3 more quarters than dimes. the coins have a total value of $
Zepler [3.9K]
D+Q=61 => D=61-Q
3+D=Q

10D+25Q=1090

10(61-Q) + 25Q=1090
610-10Q+25Q=1090

610+15Q=1090
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15Q=480

480/15=32

32 quarters
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3 years ago
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Which type of study best describes the following research most likely to be done? A teacher wants to know how fast all her stude
Yakvenalex [24]

Census

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<em>*100% CORRECT ANSWERS</em>

Question 1

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Which type of study best describes the following research most likely to be done?

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Which type of study best describes the following research most likely to be done?

A researcher is wanting to research the after effects of plant growth after a nuclear reactor meltdown and decides to study plants within a 50 mile radius of the  power plant that had a catastrophic melt down in 2011.  

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6 0
3 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos &#10;y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
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olasank [31]

Answer:

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Step-by-step explanation:

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6 0
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